Find the Vertex of the Quadratic Function: y = (x + 14)² - 14

Find the vertex of the parabola

$y=(x+14)^2-14$

To find the vertex of the parabola expressed by the equation $y = (x+14)^2 - 14$, recognize that this is given in the vertex form of a quadratic equation:

• The general vertex form of a quadratic equation is $y = a(x-h)^2 + k$, where $(h, k)$ represents the vertex of the parabola.

In the given equation:

• The $x$ term inside the parentheses is $x+14$, which can be rewritten as $x - (-14)$. This implies $h = -14$.
• The constant term outside the parentheses is $-14$, which is the $k$ value indicating the vertical shift. Hence, $k = -14$.

Therefore, the vertex of the parabola is determined by $(h, k) = (-14, -14)$.

The solution to the problem is $(-14, -14)$.