Multiply Square Roots: √2 × √3 × √1 × √4 × √2 Calculation

Radical Multiplication with Multiple Square Roots

Solve the following exercise:

23142= \sqrt{2}\cdot\sqrt{3}\cdot\sqrt{1}\cdot\sqrt{4}\cdot\sqrt{2}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the following problem
00:03 When multiplying the root of a number (A) by the root of another number (B)
00:06 The result equals the root of their product (A times B)
00:09 Apply this formula to our exercise and calculate the products
00:14 Calculate each product separately
00:27 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

23142= \sqrt{2}\cdot\sqrt{3}\cdot\sqrt{1}\cdot\sqrt{4}\cdot\sqrt{2}=

2

Step-by-step solution

In order to simplify the given expression, apply two laws of exponents:

a. Root definition as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for an exponent applied to a product in parentheses (in reverse direction):

xnyn=(xy)n x^n\cdot y^n =(x\cdot y)^n

Begin by converting the square roots to exponents using the law of exponents mentioned in a':

23142=212312112412212= \sqrt{2}\cdot\sqrt{3}\cdot\sqrt{1}\cdot\sqrt{4}\cdot\sqrt{2}= \\ \downarrow\\ 2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}\cdot1^{\frac{1}{2}}\cdot4^{\frac{1}{2}}\cdot2^{\frac{1}{2}}=

Due to the fact that there is a multiplication operation between five terms with identical exponents we are able to apply the law of exponents mentioned in b' (which of course also applies to multiplying several terms in parentheses) Combine them together in a multiplication operation inside of parentheses which are also raised to the same exponent:

212312112412212=(23142)12=4812=48 2^{\frac{1}{2}}\cdot3^{\frac{1}{2}}\cdot1^{\frac{1}{2}}\cdot4^{\frac{1}{2}}\cdot2^{\frac{1}{2}}= \\ (2\cdot3\cdot1\cdot4\cdot2)^{\frac{1}{2}}=\\ 48^{\frac{1}{2}}=\\ \boxed{\sqrt{48}}

In the final steps, we first performed the multiplication inside of the parentheses, then we once again used the root definition as an exponent mentioned earlier in a' (in reverse direction) to return to root notation.

Therefore, we can identify that the correct answer is answer b.

3

Final Answer

48 \sqrt{48}

Key Points to Remember

Essential concepts to master this topic
  • Rule: ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} for multiplying square roots
  • Technique: Combine all numbers under one radical: 2342=2342 \sqrt{2} \cdot \sqrt{3} \cdot \sqrt{4} \cdot \sqrt{2} = \sqrt{2 \cdot 3 \cdot 4 \cdot 2}
  • Check: Calculate inside radical first: 2×3×1×4×2=48 2 \times 3 \times 1 \times 4 \times 2 = 48 , so answer is 48 \sqrt{48}

Common Mistakes

Avoid these frequent errors
  • Calculating each square root separately before multiplying
    Don't find 4=2 \sqrt{4} = 2 first, then multiply 1.414 × 1.732 × 1 × 2 × 1.414 = messy decimals! This creates rounding errors and complicated calculations. Always combine all numbers under one radical first: 23142=48 \sqrt{2 \cdot 3 \cdot 1 \cdot 4 \cdot 2} = \sqrt{48} .

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why don't I just calculate each square root and then multiply them?

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While you could do this, it creates unnecessary work with decimals like 21.414 \sqrt{2} \approx 1.414 . It's much cleaner to combine first, then take the square root of the final product!

What happens to 1 \sqrt{1} in the multiplication?

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1=1 \sqrt{1} = 1 , so it doesn't change the result. When multiplying, anything times 1 stays the same. Just include the 1 in your calculation: 2×3×1×4×2=48 2 \times 3 \times 1 \times 4 \times 2 = 48 .

Should I simplify 48 \sqrt{48} further?

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The question asks for the exact result of the multiplication, which is 48 \sqrt{48} . You could simplify to 43 4\sqrt{3} , but 48 \sqrt{48} is the direct answer to this problem.

Can I use the property ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} with more than two radicals?

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Absolutely! This property extends to any number of square roots: abcd=abcd \sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c} \cdot \sqrt{d} = \sqrt{a \cdot b \cdot c \cdot d} . Just multiply all the numbers inside the radicals together.

Why is the answer 48 \sqrt{48} and not 48?

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Because we're multiplying square roots, not regular numbers! The result stays under the radical sign. Think of it this way: 486.93 \sqrt{48} \approx 6.93 , which is much different from 48.

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