If a parabola is bending downwards and its vertex is above the x-axis, then it is always negative.
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If a parabola is bending downwards and its vertex is above the x-axis, then it is always negative.
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Given the parabola is opening downwards, the quadratic formula can be defined as:
, with and .
Step 2: Because the vertex is above the x-axis (), the vertex itself is positive when considered as a point ().
Step 3: A parabola that opens downward will eventually intersect the x-axis, creating two roots unless it remains above the x-axis—which is not generally the case when is small enough. Therefore, for values of surrounding the vertex and large enough in magnitude, can be negative.
Conclusion: The parabola is not always negative as it can be positive near its vertex.
The statement in the problem is thus Incorrect.
Incorrect
The graph of the function below intersects the X-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of \( x \) where \( f\left(x\right) > 0 \).
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