Solve: 5⁴ × (1/5)⁴ - Multiplying Powers with Same Base

Exponent Laws with Reciprocal Bases

54(15)4=? 5^4\cdot(\frac{1}{5})^4=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:05 In any fraction with a negative exponent
00:09 The numerator and the denominator can be flipped in order to obtain a positive exponent
00:15 Apply this formula to our exercise
00:27 When multiplying powers with equal bases
00:30 The exponent of the result equals the sum of the exponents
00:36 Apply this formula to our exercise, and proceed to add up the exponents
00:45 Any number raised to the power of 0 equals 1
00:48 As long as the number is not 0
00:53 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

54(15)4=? 5^4\cdot(\frac{1}{5})^4=\text{?}

2

Step-by-step solution

This problem can be solved using the Law of exponents power rules for a negative power, power over a power, as well as the power rule for the product between terms with identical bases.

However we prefer to solve it in a quicker way:

To this end, the power by power law is applied to the parentheses in which the terms are multiplied, but in the opposite direction:

xnyn=(xy)n x^n\cdot y^n=(x\cdot y)^n Since in the expression in the problem there is a multiplication between two terms with identical powers, this law can be used in its opposite sense.

54(15)4=(515)4 5^4\cdot(\frac{1}{5})^4=\big(5\cdot\frac{1}{5}\big)^4 Since the multiplication in the given problem is between terms with the same power, we can apply this law in the opposite direction and write the expression as the multiplication of the bases of the terms in parentheses to which the same power is applied.

We continue and simplify the expression inside of the parentheses. We can do it quickly if inside the parentheses there is a multiplication between two opposite numbers, then their product will give the result: 1, All of the above is applied to the problem leading us to the last step:

(515)4=14=1 \big(5\cdot\frac{1}{5}\big)^4 = 1^4=1 We remember that raising the number 1 to any power will always give the result: 1, which means that:

1x=1 1^x=1 Summarizing the steps to solve the problem, we obtain the following:

54(15)4=(515)4=1 5^4\cdot(\frac{1}{5})^4=\big(5\cdot\frac{1}{5}\big)^4 =1 Therefore, the correct answer is option b.

3

Final Answer

1

Key Points to Remember

Essential concepts to master this topic
  • Law: When bases are reciprocals, apply xnyn=(xy)n x^n \cdot y^n = (xy)^n
  • Technique: 54(15)4=(515)4=14 5^4 \cdot (\frac{1}{5})^4 = (5 \cdot \frac{1}{5})^4 = 1^4
  • Check: Any number raised to any power equals 1: 14=1 1^4 = 1

Common Mistakes

Avoid these frequent errors
  • Adding exponents when multiplying different bases
    Don't use ambn=(ab)m+n a^m \cdot b^n = (ab)^{m+n} when bases are different = wrong formula! This only works when bases are identical. Always check if you can combine the bases first using xnyn=(xy)n x^n \cdot y^n = (xy)^n when exponents match.

Practice Quiz

Test your knowledge with interactive questions

Which of the following is equivalent to \( 100^0 \)?

FAQ

Everything you need to know about this question

Why can't I just add the exponents like 4 + 4 = 8?

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You can only add exponents when multiplying powers with the same base. Since 5 and 15 \frac{1}{5} are different bases, you must use the law xnyn=(xy)n x^n \cdot y^n = (xy)^n instead.

How do I know when 5 and 1/5 multiply to give 1?

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Remember that 15 \frac{1}{5} is the reciprocal of 5. Any number times its reciprocal always equals 1: 5×15=55=1 5 \times \frac{1}{5} = \frac{5}{5} = 1 .

What if the exponents were different, like 5³ × (1/5)⁴?

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When exponents are different, you cannot use xnyn=(xy)n x^n \cdot y^n = (xy)^n . You'd need to calculate each term separately first, then multiply the results.

Why does 1 raised to any power always equal 1?

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By definition, 1 multiplied by itself any number of times is still 1. So 14=1×1×1×1=1 1^4 = 1 \times 1 \times 1 \times 1 = 1 , and this works for any exponent!

Can I solve this problem a different way?

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Yes! You could rewrite (15)4 (\frac{1}{5})^4 as 1454=154 \frac{1^4}{5^4} = \frac{1}{5^4} , then calculate 54×154=5454=1 5^4 \times \frac{1}{5^4} = \frac{5^4}{5^4} = 1 . Both methods work!

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