Solve: (7² - √36÷6)/(3+3) × (5+2) | Order of Operations Challenge

Question

Check the correct answer:

$\frac{7^2-\sqrt{36}:6}{3+3}\cdot(5+2)=$

00:12 Let's solve this problem together.

00:16 First, break it down and calculate the power.

00:22 Now, find the square root of thirty-six.

00:32 Remember, always calculate what's inside parentheses first.

00:37 A number divided by itself is always one.

00:45 Next, let's work out the quotient.

00:50 And that's how we find the solution!

Before solving the exercise, let's start by simplifying the power and the root:

$7^2=7\times7=49$

$\sqrt{36}=\sqrt{6^2}=6$

Now, we arrange the exercise accordingly:

$\frac{49-6:6}{3+3}\times(5+2)=$

According to the rules of the order of operations, parentheses are solved first:

$\frac{49-6:6}{3+3}\times(7)=$

Now we focus on the fraction, we start with the division exercise in the numerator, then we add and subtract as appropriate:

$\frac{49-1}{3+3}\times(7)=\frac{48}{6}\times(7)=$

We solve the exercise from left to right, first the division exercise and finally we multiply:

$8\times7=56$

$56$