a22:a3−(3a+12:(4a⋅3))=? \frac{a^2}{2}:\frac{a}{3}-(3a+12:(4a\cdot3))=\text{?} 2a2:3a−(3a+12:(4a⋅3))=?
−1.5a−1a -1.5a-\frac{1}{a} −1.5a−a1