Subtracting Whole Numbers with Subtraction in Parentheses

๐Ÿ†Practice additional arithmetic rules

Subtraction of whole numbers with subtractions in parentheses refers to a situation where we perform the mathematical operation of subtraction on the difference of some terms that are in parentheses.

For example:

12โˆ’(3โˆ’2)=12 - (3-2) =

One way to solve this exercise will be to distribute the parentheses. To do this, we must remember that according to the law of signs of addition/ subtraction, after removing parentheses, the expressions that were inside them change their sign.

C - Subtracting Whole Numbers with Subtraction in Parentheses

That is, in our example:

12โˆ’(3โˆ’2)=12 - (3-2) =

12โˆ’3+2=12 - 3 + 2 =

9+2=119 + 2 = 11

When distributing the parentheses, we will place a โˆ’ - in front of the number 3 3 and a + + before the 2 2 .
As you can see, in both cases the sign that was inside the parentheses has switched to the opposite sign.

Another way to solve this exercise is to use the order of operations, that is to say:

12โˆ’(3โˆ’2)=12 - (3-2) =

We will start by solving the expression in parentheses by using the order of operations and we will get:

12โˆ’1=1112 - 1 = 11


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\( 70:(14\times5)= \)

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Exercises for subtracting whole numbers with subtraction in parentheses

Exercise 1

Task:

Solve the following exercise:

โˆ’30โˆ’((โˆ’41)โˆ’((โˆ’4)โˆ’(โˆ’8)))=-30-\left(\left(-41\right)-\left(\left(-4\right)-\left(-8\right)\right)\right)=

Solution:

First we solve the innermost parentheses.

โˆ’30โˆ’((โˆ’41)โˆ’((โˆ’4)+8))=-30-\left(\left(-41\right)-\left(\left(-4\right)+8\right)\right)=

Order the expression in the innermost parentheses and solve it.

โˆ’30โˆ’((โˆ’41)โˆ’(8โˆ’4))= -30-\left(\left(-41\right)-\left(8-4\right)\right)=

โˆ’30โˆ’((โˆ’41)โˆ’4)= -30-\left(\left(-41\right)-4\right)=

We break 41 41 down into 2 2 numbers to make the calculation easier.

โˆ’30โˆ’(โˆ’40โˆ’1โˆ’4)= -30-\left(-40-1-4\right)=

โˆ’30โˆ’(โˆ’40โˆ’1โˆ’4)= -30-\left(-40-1-4\right)=

โˆ’30โˆ’(โˆ’45)= -30-\left(-45\right)=

We solve according to the rules.

โˆ’30+45= -30+45=

45โˆ’30=15 45-30=15

Answer:

1515


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Exercise 2

Task:

17โˆ’(3โˆ’(โˆ’7โˆ’4))= 17-\left(3-\left(-7-4\right)\right)=

Solution:

First, we solve the innermost parentheses and break down4 4 into 2 2 terms to make the calculation easier.

17โˆ’(3โˆ’(โˆ’7โˆ’3โˆ’1))= 17-\left(3-\left(-7-3-1\right)\right)=

17โˆ’(3โˆ’(โˆ’10โˆ’1))= 17-\left(3-\left(-10-1\right)\right)=

17โˆ’(3โˆ’(โˆ’11))= 17-\left(3-\left(-11\right)\right)=

After solving the inner parentheses we continue solving the exercise that remains in parentheses.

17โˆ’(3+11)= 17-\left(3+11\right)=

17โˆ’14= 17-14=

We break down the expression to make the calculation easier.

10+7โˆ’10โˆ’4= 10+7-10-4=

We solve the exercise in two parts.

10โˆ’10=0 10-10=0

7โˆ’4=3 7-4=3

Answer:

3 3


Exercise 3

Task:

โˆ’58โˆ’((โˆ’7)โˆ’(โˆ’12))= -58-\left(\left(-7\right)-\left(-12\right)\right)=

Solution:

We solve the expression in parentheses, first reordering the minus and plus signs.

โˆ’58โˆ’(โˆ’7+12)= -58-\left(-7+12\right)=

Solve the expression in parentheses accordingly.

โˆ’58โˆ’(12โˆ’7)= -58-\left(12-7\right)=

Solve according to the rules.

โˆ’58โˆ’5= -58-5=

We break down 5 5 into 2 2 terms to make the calculation easier.

โˆ’58โˆ’2โˆ’3= -58-2-3=

โˆ’60โˆ’3=โˆ’63 -60-3=-63

Answer:

โˆ’63 -63


Do you know what the answer is?

Exercise 4

Task:

49โˆ’(53โˆ’18)= 49-\left(53-18\right)=

Solution:

First we start with the expression in parentheses and break down the 53 53 into 2 2 numbers to make the calculation easier.

49โˆ’(58โˆ’5โˆ’18)= 49-\left(58-5-18\right)=

We solve the expression in parentheses and then solve accordingly.

49โˆ’(58โˆ’18โˆ’5)= 49-\left(58-18-5\right)=

49โˆ’(40โˆ’5)= 49-\left(40-5\right)=

49โˆ’35= 49-35=

We break down the 49 49 into 2 2 numbers to make the calculation easier.

45+4โˆ’35= 45+4-35=

We reorder the operations accordingly and solve.

45โˆ’35+4= 45-35+4=

10+4=14 10+4=14

Answer:

1414


Exercise 5

Task:

37โˆ’(4โˆ’7)= 37-\left(4-7\right)=

Solution:

First we tackle the expression in parentheses and solve.

37โˆ’(โˆ’3)= 37-\left(-3\right)=

We reorder the minus and plus signs accordingly, and solve.

37+3=40 37+3=40

Answer:

40 40


Check your understanding

Review questions

What is the subtraction of whole numbers with subtraction in parentheses?

The parentheses are a grouping sign. As the name implies, they helps us to group operations where certain mathematical operations need to be performed. These parentheses indicate that the operations must be performed from the inside out, that is, first we must solve the operations that are inside the parentheses, in this case the subtraction, and then use that number in our subtraction operation.


What is the law of signs?

In order to be able to solve operations with parenthese, the law of signs for multiplication must be applied. This law can be seen as follows:

+ร—+=+ +\times+=+

+ร—โˆ’=โˆ’ +\times-=-

โˆ’ร—+=โˆ’ -\times+=-

โˆ’ร—+=โˆ’ -\times+=-


Do you think you will be able to solve it?

How to solve with parentheses?

To solve an operation with parentheses, all we have to do is complete the operations from the inside out, that is, perform the operations that are inside the parentheses and then the operations outside the parentheses. In this case we will solve the subtractions that are inside the parentheses and then we use sign laws and perform the next operation.


How to eliminate parentheses in addition and subtraction?

In order to eliminate the parentheses in an addition or a subtraction expression, we first perform the operations that are inside the parentheses, and in this way the parentheses are eliminated, let's see some examples:

Example 1

Task:

52โˆ’(25โˆ’11)= 52-\left(25-11\right)=

Solution:

We solve the subtraction inside the parentheses.

52โˆ’(14)= 52-\left(14\right)=

We remove the parentheses by applying the law of signs.

52โˆ’14= 52-14=

We break down the 14 14 into two terms to make the calculations easier.

52โˆ’12โˆ’2=40โˆ’2=38 52-12-2=40-2=38

Answer:

38 38


Example 2

Task:

36โˆ’((โˆ’3)โˆ’(โˆ’8))= 36-\left(\left(-3\right)-\left(-8\right)\right)=

Solution:

Eliminate the innermost parentheses using sign laws.

36โˆ’(โˆ’3+8)= 36-\left(-3+8\right)=

Solve the operations inside the parentheses.

36โˆ’(8โˆ’3)=36โˆ’(5) 36-\left(8-3\right)=36-\left(5\right)

Again we eliminate parentheses.

36โˆ’5=31 36-5=31

Answer:

31 31


Test your knowledge

Examples with solutions for Subtracting Whole Numbers with Subtraction in Parentheses

Exercise #1

15:(2ร—5)= 15:(2\times5)= ?

Video Solution

Step-by-Step Solution

First we need to apply the following formula:

a:(bร—c)=a:b:c a:(b\times c)=a:b:c

Therefore, we get:

15:2:5= 15:2:5=

Now, let's rewrite the exercise as a fraction:

1525= \frac{\frac{15}{2}}{5}=

Then we'll convert it to a multiplication of two fractions:

152ร—15= \frac{15}{2}\times\frac{1}{5}=

Finally, we multiply numerator by numerator and denominator by denominator, leaving us with:

1510=1510=112 \frac{15}{10}=1\frac{5}{10}=1\frac{1}{2}

Answer

112 1\frac{1}{2}

Exercise #2

10:(10:5)= 10:(10:5)=

Video Solution

Step-by-Step Solution

To solve the expression 10:(10:5) 10 : (10 : 5) , we will apply the order of operations systematically.

Step 1: Evaluate the inner division 10:5 10 : 5 .
When we compute 10:5 10 : 5 , we are finding how many times 5 fits into 10. This calculation can be expressed as:
105=2 \frac{10}{5} = 2 .

Step 2: Substitute the result from step 1 into the outer division.
Now, we substitute 10:(10:5) 10 : (10 : 5) with 10:2 10 : 2 . Once again, we apply division:
102=5 \frac{10}{2} = 5 .

Therefore, the solution to the expression 10:(10:5) 10 : (10 : 5) is 5 5 .

Answer

5 5

Exercise #3

18:(6ร—3)= 18:(6\times3)=

Video Solution

Step-by-Step Solution

To solve the expression 18รท(6ร—3) 18 \div (6 \times 3) , we need to follow the order of operations, which specifies that multiplication should be performed before division. Therefore, we proceed as follows:

  • Step 1: Calculate the operation inside the parentheses: (6ร—3)(6 \times 3).
    We multiply 66 by 33 to get 1818.
  • Step 2: Replace the multiplication expression in the original division: 18รท1818 \div 18.
  • Step 3: Perform the division: 18รท18=118 \div 18 = 1.

Thus, the result of the expression 18รท(6ร—3) 18 \div (6 \times 3) is 1\mathbf{1}.

Answer

1

Exercise #4

2โˆ’(1+1)= 2-(1+1)=

Video Solution

Step-by-Step Solution

To solve the expression 2โˆ’(1+1) 2 - (1 + 1) , follow these steps:

  • First, evaluate the expression inside the parentheses: 1+1 1 + 1 .
  • This gives 2 2 .
  • Now replace the parentheses with this result, transforming the expression to 2โˆ’2 2 - 2 .
  • The result of 2โˆ’2 2 - 2 is 0 0 .

Therefore, the solution to the expression is 0 0 .

Answer

0

Exercise #5

19โˆ’(5+11)= 19-(5+11)=

Video Solution

Step-by-Step Solution

To solve the problem 19โˆ’(5+11)19 - (5 + 11), we will follow these steps:

  • Step 1: Evaluate the expression inside the parentheses. This means we need to calculate 5+115 + 11.
  • Step 2: Once the sum inside the parentheses is found, subtract this sum from 19.

Let's work through each step:

Step 1: Calculate 5+115 + 11 which equals 16.

Step 2: Substitute 16 in place of 5+115 + 11 in the original expression. You have 19โˆ’1619 - 16.

Now, solve 19โˆ’1619 - 16, which equals 3.

Therefore, the solution to the problem is 33.

Answer

3

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