Subtraction of whole numbers with addition in parentheses refers to a situation where we must perform the mathematical operation of subtraction on the sum of some terms that are in parentheses.
In this case, we must remember that the subtraction will be performed on each and every term separately.
The rule is as follows:
Each of the terms has its own numerical value.
\( 70:(14\times5)= \)
Task:
Note:
You can solve subtraction exercises by following the order of operations.
We add the numbers in parentheses first, and then perform the subtraction.
The impressive part is that we will arrive at the same result, as we have done the same operation, only altering the order.
\( 21:(30:10)= \)
\( 10:(10:5)= \)
\( 15:(2\times5)= \) ?
Task:
Solution:
First we address the expression in parentheses.
We continue solving the expression in parentheses.
We solve the expression according to the rules.
We reorder the expression and solve.
Answer:
Task:
Solution:
We first address the expression in parentheses.
We continue with the parentheses and solve accordingly.
Answer:
\( 500:(2000:25)= \)
\( 100-(5+55)= \)
\( 87-(7+0)= \)
Task:
Solution:
First we solve the expression in parentheses, and then the rest.
Answer:
Task:
Solution:
First we solve the exercise in parentheses and then the rest.
Answer:
\( 2-(1+1)= \)
\( 19-(5+11)= \)
\( 26-(11-2)= \)
Task:
Solution:
First we solve the expression in parentheses, and then the rest.
Answer:
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The parentheses are a grouping sign. As the name implies, they helps us to group operations where certain mathematical operations need to be performed. These parentheses indicate that the operations must be performed from the inside out, that is, first we must solve the operations that are inside the parentheses, in this case the additions, and then use that number in our subtraction operation.
\( 21-(6-13)= \)
\( 18:(6\times3)= \)
\( 300:(5\times6)= \)
In order to be able to solve operations with parentheses, the law of signs for multiplication must be applied. This law can be seen as follows:
To solve an operation with parentheses, all we have to do is complete the operations from the inside out, that is, perform the operations that are inside the parentheses and then the operations outside the parentheses. In this case we will solve the subtractions that are inside the parentheses and then we use sign laws and perform the next operation.
\( 66:(360:60)= \)
\( 99:(33:10)= \)
\( 70:(14\times5)= \)
In order to eliminate the parentheses in an addition or a subtraction expression, we first perform the operations that are inside the parentheses, and in this way the parentheses are eliminated, let's see some examples:
Task:
Solving the sum inside the parentheses we get:
Here we can remove the parentheses because all the operations have already been performed.
Task:
Task:
We can perform the operation inside the parentheses or we can apply the sign law, as shown below.
\( 21:(30:10)= \)
\( 10:(10:5)= \)
\( 15:(2\times5)= \) ?
?
First we need to apply the following formula:
Therefore, we get:
Now, let's rewrite the exercise as a fraction:
Then we'll convert it to a multiplication of two fractions:
Finally, we multiply numerator by numerator and denominator by denominator, leaving us with:
To solve the expression , we will apply the order of operations systematically.
Step 1: Evaluate the inner division .
When we compute , we are finding how many times 5 fits into 10. This calculation can be expressed as:
.
Step 2: Substitute the result from step 1 into the outer division.
Now, we substitute with . Once again, we apply division:
.
Therefore, the solution to the expression is .
To solve the expression , we need to follow the order of operations, which specifies that multiplication should be performed before division. Therefore, we proceed as follows:
Thus, the result of the expression is .
1
To solve the expression , follow these steps:
Therefore, the solution to the expression is .
0
To solve the problem , we will follow these steps:
Let's work through each step:
Step 1: Calculate which equals 16.
Step 2: Substitute 16 in place of in the original expression. You have .
Now, solve , which equals 3.
Therefore, the solution to the problem is .
3
