Subtracting Whole Numbers with Addition in Parentheses

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Subtraction of whole numbers with addition in parentheses refers to a situation where we must perform the mathematical operation of subtraction on the sum of some terms that are in parentheses.
In this case, we must remember that the subtraction will be performed on each and every term separately.

The rule is as follows:

aโˆ’(b+c)=aโˆ’bโˆ’ca - (b +c) = a - b - c

a - (b +c) = a - b - c

Each of the terms has its own numerical value.

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Test yourself on additional arithmetic rules!

\( 100-(5+55)= \)

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Practice example for the subtraction of whole numbers with addition in parentheses

Task:

12โˆ’(3+2)=12 - (3+2) =

We subtract each of the numbers in parentheses from 12 separately and get:

12โˆ’3โˆ’2=12 - 3 - 2 =

9โˆ’2=9 - 2 =

77


Another practice example for subtracting whole numbers with addition in parentheses

Task:

25โˆ’(10+5)=25โˆ’10โˆ’5=25 - (10+5)= 25 - 10 - 5 =

15โˆ’5=1015 - 5 = 10

Note:

You can solve subtraction exercises by following the order of operations.
We add the numbers in parentheses first, and then perform the subtraction.
The impressive part is that we will arrive at the same result, as we have done the same operation, only altering the order.


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Exercising subtraction of whole numbers with parentheses in which there are additions:

Exercise 1

Task:

โˆ’4โˆ’((โˆ’14)+(โˆ’23))= -4-\left(\left(-14\right)+\left(-23\right)\right)=

Solution:

First we address the expression in parentheses.

โˆ’4โˆ’(โˆ’14โˆ’23)= -4-\left(-14-23\right)=

We continue solving the expression in parentheses.

โˆ’4โˆ’(โˆ’37)= -4-\left(-37\right)=

We solve the expression according to the rules.

โˆ’4+37= -4+37=

We reorder the expression and solve.

37โˆ’4=33 37-4=33

Answer:

33 33


Exercise 2

Task:

48โˆ’(35+(โˆ’3))= 48-\left(35+\left(-3\right)\right)=

Solution:

We first address the expression in parentheses.

48โˆ’(35โˆ’3)= 48-\left(35-3\right)=

We continue with the parentheses and solve accordingly.

48โˆ’32=16 48-32=16

Answer:

16 16


Do you know what the answer is?

Exercise 3

Task:

โˆ’45โˆ’(8+10)= -45-\left(8+10\right)=

Solution:

First we solve the expression in parentheses, and then the rest.

โˆ’45โˆ’18=โˆ’63 -45-18=-63

Answer:

โˆ’63 -63


Exercise 4

Task:

13โˆ’(7+4)= 13-\left(7+4\right)=

Solution:

First we solve the exercise in parentheses and then the rest.

13โˆ’11=2 13-11=2

Answer:

22


Check your understanding

Exercise 5

Task:

7โˆ’(4+2)= 7-\left(4+2\right)=

Solution:

First we solve the expression in parentheses, and then the rest.

7โˆ’6=1 7-6=1

Answer:

1 1


Review questions

What is the subtraction of whole numbers with addition in parentheses?

The parentheses are a grouping sign. As the name implies, they helps us to group operations where certain mathematical operations need to be performed. These parentheses indicate that the operations must be performed from the inside out, that is, first we must solve the operations that are inside the parentheses, in this case the additions, and then use that number in our subtraction operation.


Do you think you will be able to solve it?

What is the law of signs?

In order to be able to solve operations with parentheses, the law of signs for multiplication must be applied. This law can be seen as follows:

+ร—+=+ +\times+=+

+ร—โˆ’=โˆ’ +\times-=-

โˆ’ร—+=โˆ’ -\times+=-

โˆ’ร—+=โˆ’ -\times+=-


How to solve with parentheses?

To solve an operation with parentheses, all we have to do is complete the operations from the inside out, that is, perform the operations that are inside the parentheses and then the operations outside the parentheses. In this case we will solve the subtractions that are inside the parentheses and then we use sign laws and perform the next operation.


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How to eliminate parentheses in addition and subtraction?

In order to eliminate the parentheses in an addition or a subtraction expression, we first perform the operations that are inside the parentheses, and in this way the parentheses are eliminated, let's see some examples:

Example 1

Task:

15โˆ’(6+2)= 15-\left(6+2\right)=

Solving the sum inside the parentheses we get:

15โˆ’(8)= 15-\left(8\right)=

Here we can remove the parentheses because all the operations have already been performed.

15โˆ’8=7 15-8=7


Example 2

Task:

โˆ’8โˆ’(9โˆ’3)= -8-\left(9-3\right)=

โˆ’8โˆ’(6)=โˆ’8โˆ’6 -8-\left(6\right)=-8-6

โˆ’8โˆ’6=โˆ’14 -8-6=-14


Example 3

Task:

19โˆ’(6+5)= 19-\left(6+5\right)=

We can perform the operation inside the parentheses or we can apply the sign law, as shown below.

19โˆ’6โˆ’5=13โˆ’5 19-6-5=13-5

13โˆ’5=8 13-5=8


Do you know what the answer is?

Examples with solutions for Subtracting Whole Numbers with Addition in Parentheses

Exercise #1

100โˆ’(5+55)= 100-(5+55)=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the sum inside the parentheses.
  • Step 2: Subtract the result of the sum from 100.

Now, let's work through each step:
Step 1: Calculate 5+555 + 55, which gives 6060.
Step 2: Perform the subtraction 100โˆ’60100 - 60, which equals 4040.

Therefore, the solution to the problem is 40 40 .

Answer

40

Exercise #2

70:(14ร—5)= 70:(14\times5)=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the product of 14 14 and 5 5 .
  • Step 2: Use this product to divide 70 70 .
  • Step 3: Compare the calculated result with the given choices.

Now, let's work through each step:
Step 1: First, calculate the product of 14 14 and 5 5 . Using basic multiplication:
14ร—5=70 14 \times 5 = 70 Step 2: Divide 70 70 by the product, which is also 70 70 :
70รท70=1 70 \div 70 = 1

Therefore, the solution to the problem is 1 1 . This matches choice 1 from the provided options.

Answer

1

Exercise #3

300:(5ร—6)= 300:(5\times6)=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Compute the product 5ร—6 5 \times 6 .
  • Step 2: Perform the division operation 300รท30 300 \div 30 .

Now, let's work through each step:

Step 1: Calculate 5ร—6 5 \times 6 .

5ร—6=30 5 \times 6 = 30

Step 2: Divide 300 by the result from Step 1.

300รท30=10 300 \div 30 = 10

Therefore, the solution to the problem is 10 \boxed{10} .

This matches the choice: 10.

Answer

10

Exercise #4

21โˆ’(6โˆ’13)= 21-(6-13)=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Evaluate the inner expression 6โˆ’136 - 13
  • Step 2: Substitute the result from Step 1 into 21โˆ’resultย fromย Stepย 121 - \text{result from Step 1}

Now, let's work through each step:

Step 1: Calculate 6โˆ’136 - 13. In this calculation, we subtract 13 from 6. The result is โˆ’7-7, because when subtracting a larger number from a smaller one, the result is negative.

Step 2: Substitute โˆ’7-7 into the outer expression 21โˆ’(โˆ’7)21 - (-7). Since subtracting a negative is equivalent to adding the positive opposite, this simplifies to 21+721 + 7.

Now, compute 21+721 + 7, which equals 28.

Therefore, the solution to the problem is 2828.

Answer

28

Exercise #5

99:(33:10)= 99:(33:10)=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Perform the inner division operation.
  • Step 2: Use the result of Step 1 in the outer division operation.

Now, let's work through each step:

Step 1: Calculate 33:10 33:10 .
This operation is equivalent to dividing 33 by 10, which gives us:
3310=3.3\frac{33}{10} = 3.3.

Step 2: Use the result from Step 1 to perform the division 99:3.3 99:3.3 .
This operation now becomes:
993.3=30\frac{99}{3.3} = 30.

Therefore, the solution to the problem is 30 30 .

Answer

30

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