Solve for X: Square Root of 144 Equals Nested Cube and Fifth Roots

Nested Radicals with Exponential Simplification

Solve the following exercise:

144=x10353 \sqrt{144}=\sqrt[3]{\sqrt[5]{x^{10\cdot3}}}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the value X
00:06 Solve the power multiplication
00:16 Multiply the order of the first root by the order of the second root
00:22 Apply the order that we obtained as a root to our number
00:27 Apply this formula to our exercise
00:32 When we have a root of order (C) on a number (A) to the power of (B)
00:39 The result equals number (A) to the power of (B divided by C)
00:43 Apply this formula to our exercise
00:52 Break down 144 to 12 squared
00:57 The root cancels out the square
01:02 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

144=x10353 \sqrt{144}=\sqrt[3]{\sqrt[5]{x^{10\cdot3}}}

2

Step-by-step solution

To solve this equation, we will follow these steps:

  • Step 1: Simplify the left side of the equation 144 \sqrt{144} .
  • Step 2: Simplify the right side of the equation x3053 \sqrt[3]{\sqrt[5]{x^{30}}} .
  • Step 3: Equate the simplified expressions and solve for x x .

Let us go through these steps:

Step 1: Simplify the left side:

The left side of the equation is 144 \sqrt{144} , which simplifies to 12 12 , because 144=12 \sqrt{144} = 12 .

Step 2: Simplify the right side:

The expression on the right is x3053 \sqrt[3]{\sqrt[5]{x^{30}}} . Let's simplify it step by step:

  • First, simplify x305 \sqrt[5]{x^{30}} :
    - Using the rule amn=am/n \sqrt[n]{a^m} = a^{m/n} , we have x305=x30/5=x6 \sqrt[5]{x^{30}} = x^{30/5} = x^6 .
  • Next, simplify x63 \sqrt[3]{x^6} :
    - Again using the same rule, x63=x6/3=x2 \sqrt[3]{x^6} = x^{6/3} = x^2 .

Step 3: Equate and solve:

From the previous steps, we get:

12=x2 12 = x^2

Therefore, the solution to the equation is:
x2=12 x^2 = 12 .

3

Final Answer

x2=12 x^2=12

Key Points to Remember

Essential concepts to master this topic
  • Radical Rule: amn=am/n \sqrt[n]{a^m} = a^{m/n} converts roots to fractional exponents
  • Technique: Work from inside out: x305=x30/5=x6 \sqrt[5]{x^{30}} = x^{30/5} = x^6
  • Check: Verify x2=12 x^2 = 12 by testing that 12=(12)3053 12 = \sqrt[3]{\sqrt[5]{(\sqrt{12})^{30}}}

Common Mistakes

Avoid these frequent errors
  • Working from outside to inside with nested radicals
    Don't start with the cube root first = (x30)1/3=x10 (x^{30})^{1/3} = x^{10} , then try the fifth root! This creates more complex expressions. Always work from the innermost radical outward: x305 \sqrt[5]{x^{30}} first, then 3 \sqrt[3]{} .

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why do I work from inside to outside with nested radicals?

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Working from inside out follows the order of operations! Just like parentheses, you must simplify the innermost expression first: x305=x6 \sqrt[5]{x^{30}} = x^6 , then apply the outer radical.

How do I remember the radical-to-exponent rule?

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Think of it as "power over root": amn=am/n \sqrt[n]{a^m} = a^{m/n} . The original power becomes the numerator, and the root index becomes the denominator.

Why is the answer x2=12 x^2 = 12 instead of x=12 x = 12 ?

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After simplifying both sides, we get 12=x2 12 = x^2 . We're asked to solve for the relationship, not find the exact value of x. The answer x2=12 x^2 = 12 is the complete solution.

What does x103 x^{10 \cdot 3} mean in the original equation?

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This means x30 x^{30} because 10×3=30 10 \times 3 = 30 . The multiplication is done first in the exponent, giving us x3053 \sqrt[3]{\sqrt[5]{x^{30}}} .

Can I solve this by raising both sides to different powers?

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Yes, but it's more complex! You'd need to raise both sides to the 15th power (LCM of 3 and 5) to eliminate both radicals at once. The inside-out method is much cleaner.

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