Solve the Square Root Equation: x^6 = √16 · √25

Nested Radicals with Exponent Rules

Solve the following exercise:

x6=1625 \sqrt{x^6}=\sqrt{\sqrt{16}}\cdot\sqrt{25}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's solve this problem together.
00:14 A regular root is usually of the order two, like a square root.
00:20 We can express sixteen as four squared.
00:24 And twenty-five as five squared.
00:28 When we take the C-th root of A to the power of B,
00:31 It's like saying A to the power of B divided by C.
00:36 Let's use this formula on our exercise.
00:40 Notice that the root cancels out the square.
00:44 Now, calculate the power quotient.
00:50 We can also express four as two squared.
00:54 And again, the root cancels the square.
00:58 That's how we solve this problem, great job!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

x6=1625 \sqrt{x^6}=\sqrt{\sqrt{16}}\cdot\sqrt{25}

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify 16 \sqrt{\sqrt{16}} .
  • Step 2: Simplify 25 \sqrt{25} .
  • Step 3: Calculate the right-hand side.
  • Step 4: Solve x6= \sqrt{x^6} = computed right-hand side.

Now, let's work through each step:
Step 1: Simplify 16 \sqrt{\sqrt{16}} .
We know that 16=4 \sqrt{16} = 4 , and 4=2 \sqrt{4} = 2 . So, 16=2 \sqrt{\sqrt{16}} = 2 .

Step 2: Simplify 25 \sqrt{25} .
We know that 25=5 \sqrt{25} = 5 .

Step 3: Calculate the entire right-hand side.
We have 1625=25=10 \sqrt{\sqrt{16}} \cdot \sqrt{25} = 2 \cdot 5 = 10 .

Step 4: Solve x6=10 \sqrt{x^6} = 10 .
Rewrite the left side as (x6)1/2=x6/2=x3 (x^6)^{1/2} = x^{6/2} = x^3 .
Thus, x3=10 x^3 = 10 .

Therefore, the solution to the problem is x3=10 x^3 = 10 .

3

Final Answer

x3=10 x^3=10

Key Points to Remember

Essential concepts to master this topic
  • Radical Simplification: Work from innermost radical outward step by step
  • Technique: Use x6=x3 \sqrt{x^6} = x^3 when x ≥ 0
  • Check: Verify x3=10 x^3 = 10 gives (103)6=10 \sqrt{(\sqrt[3]{10})^6} = 10

Common Mistakes

Avoid these frequent errors
  • Incorrectly simplifying nested radicals
    Don't solve x6=10 \sqrt{x^6} = 10 by squaring both sides to get x6=100 x^6 = 100 ! This ignores that x6=x3=x3 \sqrt{x^6} = |x^3| = x^3 for non-negative x. Always simplify radicals using exponent rules first.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why does x6 \sqrt{x^6} equal x3 x^3 and not x6 x^6 ?

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Because x6=(x6)1/2=x61/2=x3 \sqrt{x^6} = (x^6)^{1/2} = x^{6 \cdot 1/2} = x^3 ! The square root means raise to the power of 1/2, not remove the radical completely.

How do I handle 16 \sqrt{\sqrt{16}} ?

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Work from the inside out: First find 16=4 \sqrt{16} = 4 , then 4=2 \sqrt{4} = 2 . So 16=2 \sqrt{\sqrt{16}} = 2 .

Why isn't the answer x=10 x = 10 ?

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Because we get x3=10 x^3 = 10 , not x=10 x = 10 ! The equation asks for the relationship between x and 10, which is x cubed equals 10.

Should I solve for the exact value of x?

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Not necessarily! The problem asks you to solve the equation, and x3=10 x^3 = 10 is the solution. If you need the decimal value, then x=1032.15 x = \sqrt[3]{10} \approx 2.15 .

What if x could be negative?

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For this problem, we assume x0 x ≥ 0 since we're dealing with x6 \sqrt{x^6} . If x were negative, we'd need to consider absolute values: x6=x3 \sqrt{x^6} = |x^3| .

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