Solve log₁₀3 + log₁₀4: Step-by-Step Logarithm Addition

Question

log103+log104= \log_{10}3+\log_{10}4=

Video Solution

Solution Steps

00:00 Solve
00:03 We'll use the formula for adding logarithms
00:16 We'll use this formula in our exercise
00:23 We can see it's applicable, bases are equal
00:39 Let's solve the parentheses
00:44 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we will use the property of logarithms that allows us to combine the sum of two logarithms:

  • Step 1: Identify the formula. We use the property logb(x)+logb(y)=logb(xy)\log_b(x) + \log_b(y) = \log_b(x \cdot y) where both logarithms must have the same base.
  • Step 2: Recognize the base. Here, both logarithms are in base 10: log103\log_{10}3 and log104\log_{10}4.
  • Step 3: Apply the property. Add the two logarithms using the formula: log103+log104=log10(34)\log_{10}3 + \log_{10}4 = \log_{10}(3 \cdot 4).
  • Step 4: Perform the multiplication. Compute 343 \cdot 4 to get 12.
  • Step 5: Express the result as a single logarithm: log1012\log_{10}12.

Therefore, the expression log103+log104\log_{10}3 + \log_{10}4 simplifies to log1012\log_{10}12.

Answer

log1012 \log_{10}12