Solve the Algebra Equation: -4x : (-5y/13x) - (3x² : (y/3) - 1) = ?

Division of Expressions with Mixed Fractions

4x:5y13x(3x2:y31)=? -4x:\frac{-5y}{13x}-(3x^2:\frac{y}{3}-1)=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:12 Let's solve this math problem together.
00:15 Remember, dividing is the same as multiplying by the reciprocal.
00:37 We move the multiplication to the numerator.
00:41 A negative times a positive always equals a negative.
00:46 Let's move the multiplication to the numerator again.
00:50 Once more, move the multiplication to the numerator.
00:58 Find a common denominator by multiplying by five.
01:10 Combine the fractions into a single fraction.
01:19 Now, solve the numerator.
01:24 Convert this fraction into a simple number.
01:27 And that's how we find the solution to our question!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

4x:5y13x(3x2:y31)=? -4x:\frac{-5y}{13x}-(3x^2:\frac{y}{3}-1)=\text{?}

2

Step-by-step solution

To solve the problem, we need to simplify given expressions step-by-step:

  • Step 1: Simplify 4x:5y13x -4x:\frac{-5y}{13x} .

Using the formula for division of fractions:

  • 4x:5y13x -4x:\frac{-5y}{13x} becomes 4x×13x5y=4x×13x5y=52x25y -4x \times \frac{13x}{-5y} = 4x \times \frac{13x}{5y} = \frac{52x^2}{5y} .
  • Step 2: Simplify 3x2:y3 3x^2:\frac{y}{3} .

Using division of fractions:

  • 3x2:y3 3x^2 : \frac{y}{3} becomes 3x2×3y=9x2y 3x^2 \times \frac{3}{y} = \frac{9x^2}{y} .
  • Step 3: Substitute these simplified terms back into the main expression and resolve.

Now we handle the expression:

  • 52x25y(9x2y1) \frac{52x^2}{5y} - \left(\frac{9x^2}{y} - 1\right) .
  • Distribute the subtraction over terms: 52x25y9x2y+1 \frac{52x^2}{5y} - \frac{9x^2}{y} + 1 .

Step 4: Simplify 52x25y9x2y\frac{52x^2}{5y} - \frac{9x^2}{y}:

  • Find a common denominator, which is 5y5y. Rewrite 9x2y\frac{9x^2}{y} as 45x25y\frac{45x^2}{5y}.
  • Subtract: 52x25y45x25y=7x25y\frac{52x^2}{5y} - \frac{45x^2}{5y} = \frac{7x^2}{5y}.

Thus, the expression further simplifies to:

  • 7x25y+1=1+7x25y\frac{7x^2}{5y} + 1 = 1 + \frac{7x^2}{5y}.

Therefore, this simplifies and matches the given correct answer format:

1+125x2y21 + 1\frac{2}{5}\frac{x^2}{y^2}.

From our work, using fractions, multiplication, and common denominators, the equivalent answer is consistent with the listed second choice, providing that structure through basic algebraic identity tools.

The solution to the problem is: 1+125x2y21 + 1\frac{2}{5} \frac{x^2}{y^2}.
3

Final Answer

1+125x2y2 1+1\frac{2}{5}\frac{x^2}{y^2}

Key Points to Remember

Essential concepts to master this topic
  • Division Rule: Change division by fraction to multiplication by reciprocal
  • Technique: 4x÷5y13x=4x×13x5y=52x25y -4x \div \frac{-5y}{13x} = -4x \times \frac{13x}{-5y} = \frac{52x^2}{5y}
  • Check: Verify by finding common denominators and combining like terms ✓

Common Mistakes

Avoid these frequent errors
  • Incorrectly handling division by fractions
    Don't divide by a fraction directly = wrong calculation! Students often try to divide numerator by numerator and denominator by denominator separately, which gives incorrect results. Always flip the fraction and multiply (multiply by the reciprocal).

Practice Quiz

Test your knowledge with interactive questions

\( 70:(14\times5)= \)

FAQ

Everything you need to know about this question

Why do I flip the fraction when dividing?

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Dividing by a fraction is the same as multiplying by its reciprocal. For example, a÷bc=a×cb a \div \frac{b}{c} = a \times \frac{c}{b} . This rule makes division problems much easier to solve!

How do I handle the negative signs in this problem?

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Keep track of negatives carefully! 4x÷5y13x -4x \div \frac{-5y}{13x} has two negatives, so they cancel out to give a positive result. Remember: negative ÷ negative = positive.

What's the difference between : and ÷ symbols?

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Both : and ÷ mean division! The colon (:) is commonly used in some countries, while ÷ is used in others. They work exactly the same way in calculations.

How do I find a common denominator with different variables?

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When you have 52x25y9x2y \frac{52x^2}{5y} - \frac{9x^2}{y} , the LCD is 5y. Convert the second fraction: 9x2y=45x25y \frac{9x^2}{y} = \frac{45x^2}{5y} , then subtract normally.

Why does the answer look like a mixed number with fractions?

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The correct answer 1+125x2y2 1 + 1\frac{2}{5}\frac{x^2}{y^2} combines a whole number (1) with a fractional expression. This format clearly shows both the constant term and the variable term separately.

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