Solve the Complex Equation: 130÷(10/2x)-(23x-204)

Question

130:102x(23x204)=? 130:\frac{10}{2x}-(23x-204)=\text{?}

Video Solution

Solution Steps

00:00 Solve
00:05 Division is also multiplication by the reciprocal
00:12 Negative times positive is always negative
00:16 Negative times negative is always positive
00:24 Let's factor 130 into factors 10 and 13
00:36 Let's reduce what we can
00:47 Let's group factors
00:52 And this is the solution to the question

Step-by-Step Solution

To solve the given expression 130:102x(23x204) 130 : \frac{10}{2x} - (23x - 204) , follow these steps:

  • Firstly, simplify the fraction 102x \frac{10}{2x} to get 5x \frac{5}{x} .
  • Next, perform the division 130÷5x 130 \div \frac{5}{x} . This is equivalent to multiplying 130 130 by the reciprocal, resulting in 130×x5 130 \times \frac{x}{5} . Simplify this to get 26x 26x .
  • The expression now becomes 26x(23x204) 26x - (23x - 204) .
  • Distribute the negative sign inside the parentheses to get 26x23x+204 26x - 23x + 204 .
  • Simplify by combining like terms, which yields 3x+204 3x + 204 .

Therefore, the solution to the problem is 3x+204 3x + 204 . This matches option 1 from our choices, confirming it as the correct answer.

Answer

3x+204 3x+204