Solve the Fraction Equation: Finding the Missing Term with 2/5a and 3/4ab

Fill in the gap so that the equation is satisfied:

25a+34ab+23b=a+13b+13b \frac{2}{5}a+\frac{3}{4}ab+\frac{2}{3}b=_—a+\frac{1}{3}b+\frac{1}{3}b

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the unknown
00:18 Gather the factors
00:21 Isolate the unknown, and solve to find it
00:26 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the gap so that the equation is satisfied:

25a+34ab+23b=a+13b+13b \frac{2}{5}a+\frac{3}{4}ab+\frac{2}{3}b=_—a+\frac{1}{3}b+\frac{1}{3}b

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Compare the given equation with the incomplete side.

  • Step 2: Isolate terms involving the same variables for comparison.

  • Step 3: Calculate the required terms to balance the equation.

Now, let's work through each step:

Step 1: The equation is given:
25a+34ab+23b=_a+13b+13b \frac{2}{5}a + \frac{3}{4}ab + \frac{2}{3}b = \_ - a + \frac{1}{3}b + \frac{1}{3}b

Step 2: Combine like terms on the right side. Notice 13b+13b=23b\frac{1}{3}b + \frac{1}{3}b = \frac{2}{3}b.

The equation becomes:
25a+34ab+23b=_a+23b \frac{2}{5}a + \frac{3}{4}ab + \frac{2}{3}b = \_ - a + \frac{2}{3}b

Step 3: Compare the terms involving aa, bb, and constants:

  • Terms with aa: 25a\frac{2}{5}a should remain, meaning we need to offset the a-a.

  • To balance: a(25)=25aa(\frac{2}{5}) = \frac{2}{5}a

  • Terms with abab: 34ab\frac{3}{4}ab needs to be transferred directly.

Since - on right side requires its cancellation, a plus 34b\frac{3}{4}b on missing term substitutes division. Hence,25+34b \frac{2}{5} + \frac{3}{4}b is needed to balance and supplement.

Therefore, the solution to the problem is 25+34b \frac{2}{5} + \frac{3}{4}b , which matches choice 4.

3

Final Answer

25+34b \frac{2}{5}+\frac{3}{4}b

Practice Quiz

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Are the expressions the same or not?

\( 3+3+3+3 \)

\( 3\times4 \)

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