Equivalent Expressions

๐Ÿ†Practice variables and algebraic expressions

In previous articles, we have talked about what an algebraic expression is and how to get the numerical value of algebraic expressions. Today, we will cover equivalent expressions.

Equivalent expressions are two or more algebraic expressions that represent the same value. They may have a different structure, but their numerical value will be the same.

For example, in the following equation both sides represent the same quantity:

9X=3X+6X 9X=3X+6X

Below is another example with 2 variables. By simplifying the expressions on both sides of the equation, we can work out that on both we have 2Xโˆ’3Y+5 2X-3Y+5 and therefore the expressions are equivalent.

2Xโˆ’3Y+5=X+Xโˆ’2Y+10โˆ’5โˆ’Y 2X-3Y+5=X+X-2Y+10-5-Y

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Test yourself on variables and algebraic expressions!

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\( 3x+4x+7+2=\text{?} \)

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Here are some examples:

  • 1+1=2 1+1=2
  • 2โˆ’0=2 2-0=2
  • 7X=2X+5X 7X=2X+5X
  • 4Xร—(2+3)=8X+12X 4X\times\left(2+3\right)=8X+12X
  • 8X+12X=20X 8X+12X=20X

Practicing Equivalent Expressions

Exercise 1

Write an equivalent expression for the following:

0 0

Solution

We look for an expression that represents 0 0 , for example:

0=5โˆ’5 0=5-5


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Exercise 2

3+3+3 3+3+3

Solution

To do this exercise, we must first work out that the expression represents 9 9 before looking for an equivalent form.

3+3+3=10โˆ’1 3+3+3=10-1


Exercise 3

7X 7X

Solution

We look for a way to represent 7X 7X , e.g.:

7x=4x+2x+x 7x=4x+2x+x


Do you know what the answer is?

Exercise 4

13Xโˆ’3 13Xโˆ’3

Solution

We look for an equivalent way of representing 13X 13X and โˆ’3 -3, for instance:

13xโˆ’3=15xโˆ’2xโˆ’2โˆ’1 13x-3=15x-2x-2-1


Exercise 5

1.5X+8+6.5X 1.5X+8+6.5X

Solution

As the expression represents 8X+8 8X+8 , we need to look for an alternative way to represent each term:

1.5x+8+6.5x=10xโˆ’2x+5+3 1.5x+8+6.5x=10x-2x+5+3


Check your understanding

Which of the following expressions are are equivalent?

Exercise 6

18X 18X

2+9X 2+9X

Solution

The expressions are not equivalent. One represents 18X 18X while the other one represents 9X 9X .


Exercise 7

20X 20X

2ร—10X 2\times10X

Solution

The expressions are equivalent as both represent 20X 20X .


Do you think you will be able to solve it?

Exercise 8

3+3+3+3 3+3+3+3

3ร—4 3\times4

Solution

The expressions are equivalent because both represent the number 12 12 .


Exercise 9

15Xโˆ’30 15Xโˆ’30

45โˆ’15โˆ’5X+15X 45-15-5X+15X

Solution

The expressions are not equivalent. The first one represents 15X 15X while the second one represents only 10X 10X .


Test your knowledge

Exercise 10

0.5Xร—1 0.5X\times1

0.5X+0 0.5X+0

Solution

The expressions are equivalent.


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Questions and Answers: Equivalent Expressions

What is an algebraic expression?

An algebraic expression is a combination of numbers, letters (representing unknown numbers), and arithmetic operations.


What are equivalent algebraic expressions?

They are algebraic expressions that have different structures but represent the same value.


How to find equivalent expressions?

We try to modify the structure of the expression so that the value it represents is not altered.


Do you know what the answer is?

Additional Examples

It is important that we learn to write equivalent algebraic expressions in their simplest form since this will be very useful when solving equations.

Exercise 1

Simplify 2x+5x+x 2x+5x+x

Solution:

To find an equivalent expression we add the coefficients of each term together.

(2+5+1)x=8x \left(2+5+1\right)x=8x


Check your understanding

Exercise 2

Reduce the expression 8m+8โˆ’6m+3 8m+8-6m+3

Solution:

We separate the terms that have m m from those that do not and perform the indicated operations.

8m+8โˆ’6m+3=8mโˆ’6m+8+3=(8โˆ’6)m+11=2m+11 8m+8-6m+3=8m-6m+8+3=(8-6)m+11=2m+11


Exercise 3

Find a simpler equivalent form for the expression 8x+2yโˆ’3z+3yโˆ’4x+3z 8x+2y-3z+3y-4x+3z

Solution:

We first group the terms that have the same letter and then perform the indicated operations.

8x+2yโˆ’3z+3yโˆ’4x+3z=8xโˆ’4x+2y+3yโˆ’3z+3z=(8โˆ’4)x+(2+3)y+(โˆ’3+3)z=4x+5y+0z=4x+5y 8x+2y-3z+3y-4x+3z=8x-4x+2y+3y-3z+3z=(8-4)x+\left(2+3\right)y+\left(-3+3\right)z=4x+5y+0z=4x+5y


Do you think you will be able to solve it?

Exercise 4

Simplify the expression 6x+1โˆ’2x+3 6x+1-2x+3 . Then substitute the value x=3 in to both expressions and verify that you get the same numerical value.

Solution:

First we simplify the expression.

6x+1โˆ’2x+3=6xโˆ’2x+1+3=4x+4 6x+1-2x+3=6x-2x+1+3=4x+4

Now we substitute x=3 x=3 in to both expressions.

6(3)+1โˆ’2(3)+3=18+1โˆ’6+3=18+1+3โˆ’6=22โˆ’6=16 6\left(3\right)+1-2\left(3\right)+3=18+1-6+3=18+1+3-6=22-6=16

4(3)+4=12+4=16 4\left(3\right)+4=12+4=16

We do indeed get the same numerical value from both expressions.


Exercise 5

Solve the equation 5x+2+3x+7โˆ’2xโˆ’5=16 5x+2+3x+7-2x-5=16

Solution:

First, find an equivalent expression:

5x+2+3x+7โˆ’2xโˆ’5=16 5x+2+3x+7-2x-5=16

5x+3xโˆ’2x+2+7โˆ’5=16 5x+3x-2x+2+7-5=16

(5+3โˆ’2)x+4=16 \left(5+3-2\right)x+4=16

6x+4=16 6x+4=16

Now solve for x x :

6x=16โˆ’4 6x=16-4

6x=12 6x=12

x=126 x=\frac{12}{6}

x=2 x=2


Test your knowledge

Examples with solutions for Equivalent Expressions

Exercise #1

3x+4x+7+2=? 3x+4x+7+2=\text{?}

Video Solution

Step-by-Step Solution

Let's simplify the expression 3x+4x+7+2 3x + 4x + 7 + 2 step-by-step:

  • Step 1: Combine Like Terms Involving x x
    The terms 3x 3x and 4x 4x are like terms because both involve the variable x x . To combine them, add their coefficients:
    3x+4x=(3+4)x=7x 3x + 4x = (3 + 4)x = 7x

  • Step 2: Combine Constant Terms
    The expression includes constant terms 7 7 and 2 2 . These can be added together to simplify:
    7+2=9 7 + 2 = 9

  • Step 3: Write the Simplified Expression
    Now, combine the results from Step 1 and Step 2 to form the final simplified expression:
    7x+9 7x + 9

Therefore, the simplified expression is 7x+9 7x + 9 .

Reviewing the choices provided, the correct choice is:

  • Choice 2: 7x+9 7x + 9

This matches our simplified expression, confirming our solution is correct.

Answer

7x+9 7x+9

Exercise #2

3z+19zโˆ’4z=? 3z+19z-4z=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Combine like terms by identifying and adding their coefficients.
  • Step 2: Simplify the expression.
  • Step 3: Verify the resulting expression with the provided choices.

Let's work through each step:

Step 1: Identify the coefficients in the expression 3z+19zโˆ’4z 3z + 19z - 4z . The coefficients are 3 3 , 19 19 , and โˆ’4 -4 .

Step 2: Add and subtract these coefficients: 3+19โˆ’4 3 + 19 - 4 .

Step 3: Calculate: 3+19=22 3 + 19 = 22 and then 22โˆ’4=18 22 - 4 = 18 .

Therefore, the simplified expression is 18z 18z .

The solution to the problem is 18z 18z .

Answer

18z 18z

Exercise #3

11+5xโˆ’2x+8= 11+5x-2x+8=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the like terms in the expression.
  • Step 2: Combine the constant terms.
  • Step 3: Combine the coefficients of xx.

Now, let's work through each step:
Step 1: The given expression is 11+5xโˆ’2x+811 + 5x - 2x + 8. There are constants (11 and 8) and terms with xx (5x and -2x).
Step 2: Combine the constants: 11+8=1911 + 8 = 19.
Step 3: Combine the coefficients of xx: 5xโˆ’2x=3x5x - 2x = 3x.

After simplification, the expression becomes 19+3x19 + 3x.

The correct solution from the multiple-choice options is 19+3x\boxed{19 + 3x}.

Answer

19+3X

Exercise #4

5+0+8xโˆ’5= 5+0+8x-5=

Video Solution

Step-by-Step Solution

To simplify the expression 5+0+8xโˆ’55 + 0 + 8x - 5, follow these steps:

  • Step 1: Identify and group like terms. In this case, there are constants (5, 0, -5) and a term with a variable (8x).
  • Step 2: Combine the constants: 5+0โˆ’55 + 0 - 5.
  • Step 3: Calculate: 5โˆ’5=05 - 5 = 0.

Now, our expression simplifies to 0+8x0 + 8x, which is simply 8x8x.

Therefore, the simplified expression is 8x8x.

Answer

8X 8X

Exercise #5

5+8โˆ’9+5xโˆ’4x= 5+8-9+5x-4x=

Video Solution

Step-by-Step Solution

To solve this problem, we will simplify the expression 5+8โˆ’9+5xโˆ’4x5+8-9+5x-4x by separately combining the constants and the variable terms.

Step 1: Simplify the constant terms.
5+8โˆ’9=45 + 8 - 9 = 4

Step 2: Simplify the variable terms.
5xโˆ’4x=x5x - 4x = x

Step 3: Combine the results from steps 1 and 2.
Thus, the simplified expression is 4+x4 + x.

Therefore, the solution to the problem is 4+x4 + x, which corresponds to choice .

Answer

4+X

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