Simplifying Expressions (Collecting Like Terms)

πŸ†Practice variables and algebraic expressions

The simplification of expressions consists of creating an equivalent expression written in a shorter and simpler way in which we combine all of the similar terms (collecting like terms).

For example, the expression:

3+3+3+3+3+5Xβˆ’3X 3+3+3+3+3+5X-3X

After having simplified it, it would be:

15+2X 15+2X

What we have done is created two groups of numbers and variables:
3+3+3+3+3 3+3+3+3+3 and 5Xβˆ’3X 5X-3X .

This can be simplified further, resulting in only two terms:15+2X 15+2X

Solving a basic algebraic equation: X + 3X = 8 + 4. Step-by-step breakdown of combining like terms on both sides to get 4X = 12. Fundamental algebra simplification process.

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Test yourself on variables and algebraic expressions!

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\( 3x+4x+7+2=\text{?} \)

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After having studied what algebraic expressions and equivalent algebraic expressions are, the next thing to do is to understand how to collect like terms.

Since the numbers and variables are not similar (or, 'like') terms, they cannot be simplified into a single group and, therefore, we have to write them separately (X,Y X,Y).

Example with Two Variables

The expression 4+2+2X+3X+Y+2Y= 4+2+2X+3X+Y+2Y= can be simplified as follows:

5X+3Y+6 5X+3Y+6

Practice Exercises: Collecting Like Terms

Combine like terms in order to obtain shorter expressions:

  • X+X=X+X=
  • 5+8βˆ’9+5Xβˆ’4X=5+8-9+5X-4X=
  • 5+0+8Xβˆ’5=5+0+8X-5=
  • 11+5Xβˆ’2X+8=11+5X-2X+8=
  • 13X+5βˆ’4.5X+7.5X=13X+5-4.5X+7.5X=

Collect like terms to obtain shorter expressions. Then, using what we have learned about the numerical value of algebraic expressions, apply X=5 X=5 and solve.

  • 2X+5Xβ‹…4=2X+5X\cdot4=
  • 2.3X+0.4Xβˆ’0.7X=2.3X+0.4X-0.7X=
  • X15+X15={X\over15}+{X\over15}=
  • 38Xβˆ’28X+5={3\over8}X-{2\over8}X+5=
  • (7+Y):3=(7+Y):3=

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Exercises: Collecting Like Terms

Exercise 1

Task:

3baβ‹…138a+58b+418m+910a+23m=?3\frac{b}{a}\cdot1\frac{3}{8}a+\frac{5}{8}b+\frac{4}{18}m+\frac{9}{10}a+\frac{2}{3}m=\text{?}

Solution:

Enter the corresponding elements.

3baΓ—138a+58b+910a+418m+23m=3\frac{b}{a}\times1\frac{3}{8}a+\frac{5}{8}b+\frac{9}{10}a+\frac{4}{18}m+\frac{2}{3}m=

Convert the mixed fractions into improper fractions.

3baΓ—(8+3)8a+58b+910a+418m+23m=3\frac{b}{a}\times\frac{(8+3)}{8}a+\frac{5}{8}b+\frac{9}{10}a+\frac{4}{18}m+\frac{2}{3}m=

Solve accordingly.

3Γ—11Γ—bΓ—a8Γ—a+58b+910a+4+2Γ—618m= \frac{3\times11\times b\times a}{8\times a}+\frac{5}{8}b+\frac{9}{10}a+\frac{4+2\times6}{18}m=

Simplify to a a in the equation.

338b+58b+910a+1618m=\frac{33}{8}b+\frac{5}{8}b+\frac{9}{10}a+\frac{16}{18}m=

33+58b+910a+89m= \frac{33+5}{8}b+\frac{9}{10}a+\frac{8}{9}m=

388b+910a+89m= \frac{38}{8}b+\frac{9}{10}a+\frac{8}{9}m=

434b+910a+89m= 4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m=

Answer:

434b+910a+89m= 4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m=


Exercise 2

Task:

38a+149b+119b+68a=?\frac{3}{8}a+\frac{14}{9}b+1\frac{1}{9}b+\frac{6}{8}a=\text{?}

Solution:

First, group the terms together:

38a+68a+149b+119b\frac{3}{8}a+\frac{6}{8}a+\frac{14}{9}b+1\frac{1}{9}b

Then reduce in correspondence and convert the mixed fractions into improper fractions.

3+68a+109b+149b= \frac{3+6}{8}a+\frac{10}{9}b+\frac{14}{9}b=

98a+10+149b= \frac{9}{8}a+\frac{10+14}{9}b=

118a+249b= 1\frac{1}{8}a+\frac{24}{9}b=

118a+269b= 1\frac{1}{8}a+2\frac{6}{9}b=

118a+223b 1\frac{1}{8}a+2\frac{2}{3}b

Answer:

118a+223b 1\frac{1}{8}a+2\frac{2}{3}b


Do you know what the answer is?

Exercise 3

7.3Γ—4a+2.3+8a=? 7.3\times4a+2.3+8a=?

Solution:

We start with the multiplication operation.

(7.3Γ—4a)+2.3+8a= (7.3\times4a)+2.3+8a=

(29.2a)+2.3+8a= (29.2a)+2.3+8a=

Then we add together as much as we can and rewrite the equation to make it clearer:

29.2a+8a+2.3= 29.2a+8a+2.3=

37.2a+2.3= 37.2a+2.3=

Answer:

37.2a+2.3 37.2a+2.3


Exercise 4

Task:

Solve the following equation:

a+b+bc+9a+10b+3c=? a+b+bc+9a+10b+3c=\text{?}

Solution:

The terms are substituted into the expression according to the order: a,b,ca, b, c.

a+9a+b+bc+10b+3c= a+9a+b+bc+10b+3c=

We continue with the addition operations.

10a+11b+bc+3c= 10a+11b+bc+3c=

The terms containing cc are converted for the equation since they cannot be simplified further.

10a+11b+(b+3)c 10a+11b+(b+3)c

Answer:

10a+11b+(b+3)c 10a+11b+(b+3)c


Check your understanding

Exercise 5

Task:

Solve the following equation:

3z+19zβˆ’4z=? 3z+19z-4z=\text{?}

Solution:

We start with the addition operation:

22zβˆ’4z= 22z-4z=

We continue solving accordingly.

18z 18z

Answer:

18z 18z


Review Questions

What are like terms?

Like terms in an algebraic expression are those that have the same variable with the same exponent, regardless of the sign and the coefficientβ€”that is, the sign and the coefficient can be different, but the variable and the exponent must be the same. For example:

3x2 3x^2 y βˆ’11x2 -11x^2

8a5 8a^5 y 8a5 8a^5

βˆ’7m -7m y 23m \frac{2}{3}m


How do you simplify expressions?

In order to simplify algebraic expressions, we need to work out if there are any like terms and then group them together before performing the operations (addition, subtraction, etc.).

Example 1

Task: Simplify the following expression:

3x2βˆ’7x+6βˆ’5x2βˆ’xβˆ’1 3x^2-7x+6-5x^2-x-1

Solution:

First we need to group the like terms and then perform the operations.

3x2βˆ’5x2βˆ’7xβˆ’x+6βˆ’1 3x^2-5x^2-7x-x+6-1

βˆ’2x2βˆ’8x+5 -2x^2-8x+5

Answer:

βˆ’2x2βˆ’8x+5 -2x^2-8x+5

Example 2

Task: Simplify the following expression:

8m2+2m+7=3m3+5m2+2mβˆ’5 8m^2+2m+7=3m^3+5m^2+2m-5

Solution:

In this case we need to put all the terms on one side and combine the like terms:

βˆ’3m3+8m2βˆ’5m2+2mβˆ’2m+7+5= -3m^3+8m^2-5m^2+2m-2m+7+5=

βˆ’3m3+3m2+12= -3m^3+3m^2+12=

Answer:

βˆ’3m3+3m2+12= -3m^3+3m^2+12=


How do you simplify a function?

In order to simplify a function, we must also work out if there are any like terms and group them together in order to simplify them.

Example

Question: Simplify the following function:

f(a)=βˆ’5a2+2aβˆ’4+2a2+5a f\left(a\right)=-5a^2+2a-4+2a^2+5a

Solution:

In this function we can see that there are like terms, so we can group them to simplify them.

f(a)=βˆ’5a2+2a2+2a+5aβˆ’4 f\left(a\right)=-5a^2+2a^2+2a+5a-4

f(a)=βˆ’3a2+7aβˆ’4 f\left(a\right)=-3a^2+7a-4

Answer:

f(a)=βˆ’3a2+7aβˆ’4 f\left(a\right)=-3a^2+7a-4


Do you think you will be able to solve it?

Examples with solutions for Simplifying Expressions (Collecting Like Terms)

Exercise #1

3x+4x+7+2=? 3x+4x+7+2=\text{?}

Video Solution

Step-by-Step Solution

Let's simplify the expression 3x+4x+7+2 3x + 4x + 7 + 2 step-by-step:

  • Step 1: Combine Like Terms Involving x x
    The terms 3x 3x and 4x 4x are like terms because both involve the variable x x . To combine them, add their coefficients:
    3x+4x=(3+4)x=7x 3x + 4x = (3 + 4)x = 7x

  • Step 2: Combine Constant Terms
    The expression includes constant terms 7 7 and 2 2 . These can be added together to simplify:
    7+2=9 7 + 2 = 9

  • Step 3: Write the Simplified Expression
    Now, combine the results from Step 1 and Step 2 to form the final simplified expression:
    7x+9 7x + 9

Therefore, the simplified expression is 7x+9 7x + 9 .

Reviewing the choices provided, the correct choice is:

  • Choice 2: 7x+9 7x + 9

This matches our simplified expression, confirming our solution is correct.

Answer

7x+9 7x+9

Exercise #2

3z+19zβˆ’4z=? 3z+19z-4z=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Combine like terms by identifying and adding their coefficients.
  • Step 2: Simplify the expression.
  • Step 3: Verify the resulting expression with the provided choices.

Let's work through each step:

Step 1: Identify the coefficients in the expression 3z+19zβˆ’4z 3z + 19z - 4z . The coefficients are 3 3 , 19 19 , and βˆ’4 -4 .

Step 2: Add and subtract these coefficients: 3+19βˆ’4 3 + 19 - 4 .

Step 3: Calculate: 3+19=22 3 + 19 = 22 and then 22βˆ’4=18 22 - 4 = 18 .

Therefore, the simplified expression is 18z 18z .

The solution to the problem is 18z 18z .

Answer

18z 18z

Exercise #3

11+5xβˆ’2x+8= 11+5x-2x+8=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the like terms in the expression.
  • Step 2: Combine the constant terms.
  • Step 3: Combine the coefficients of xx.

Now, let's work through each step:
Step 1: The given expression is 11+5xβˆ’2x+811 + 5x - 2x + 8. There are constants (11 and 8) and terms with xx (5x and -2x).
Step 2: Combine the constants: 11+8=1911 + 8 = 19.
Step 3: Combine the coefficients of xx: 5xβˆ’2x=3x5x - 2x = 3x.

After simplification, the expression becomes 19+3x19 + 3x.

The correct solution from the multiple-choice options is 19+3x\boxed{19 + 3x}.

Answer

19+3X

Exercise #4

5+0+8xβˆ’5= 5+0+8x-5=

Video Solution

Step-by-Step Solution

To simplify the expression 5+0+8xβˆ’55 + 0 + 8x - 5, follow these steps:

  • Step 1: Identify and group like terms. In this case, there are constants (5, 0, -5) and a term with a variable (8x).
  • Step 2: Combine the constants: 5+0βˆ’55 + 0 - 5.
  • Step 3: Calculate: 5βˆ’5=05 - 5 = 0.

Now, our expression simplifies to 0+8x0 + 8x, which is simply 8x8x.

Therefore, the simplified expression is 8x8x.

Answer

8X 8X

Exercise #5

5+8βˆ’9+5xβˆ’4x= 5+8-9+5x-4x=

Video Solution

Step-by-Step Solution

To solve this problem, we will simplify the expression 5+8βˆ’9+5xβˆ’4x5+8-9+5x-4x by separately combining the constants and the variable terms.

Step 1: Simplify the constant terms.
5+8βˆ’9=45 + 8 - 9 = 4

Step 2: Simplify the variable terms.
5xβˆ’4x=x5x - 4x = x

Step 3: Combine the results from steps 1 and 2.
Thus, the simplified expression is 4+x4 + x.

Therefore, the solution to the problem is 4+x4 + x, which corresponds to choice .

Answer

4+X

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