Variables in Algebraic Expressions

๐Ÿ†Practice variables and algebraic expressions

When a problem is presented to us in writing, we can convert it into mathematical language (also called algebraic language) by transforming it into an algebraic expression. But what are algebraic expressions?

Variable: This is a letter that represents a numerical value, for example X X or Y Y . This letter refers to an unknown numerical value that we must work out. For example: if X+5=8 X+5=8 , then we can conclude that the numerical value of X X is 3 3 .

An algebraic expression is a combination of numbers and letters (representing unknown numbers) that includes operations such as addition, subtraction, multiplication, division, etc.

Each element of an algebraic expression is called an algebraic term, be it a variable, a constant, or a combination of a coefficient and one or more variables. If the expression contains only one term, it is known as a monomial, while those that contain two or more terms are polynomials.

Labeled algebraic equation illustrating parts of an expression: terms, coefficients, variables, constants, and the full equation, using color-coded annotations for clarity.

There is no limitation to the amount of constant numbers, unknown variables, or operations that can appear in an algebraic expression. In addition, there does not always have to be a variable in the algebraic expression, although it will always have a certain numerical value.

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Test yourself on variables and algebraic expressions!

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\( 3x+4x+7+2=\text{?} \)

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Examples of Algebraic Expressions

Let's take a look at some examples of algebraic expressions without variables:

4+74+7

93 \frac{9}{3}

3โˆ’23-2

2ร—8 2\times8

Here we can see that all of the expressions are composed of numbers and, since there are no unknown variables, we can calculate the result by simply performing the operations.

4+7=11 4+7 =11

93=3 \frac{9}{3}=3

3โˆ’2=1 3-2=1

2ร—8=16 2\times8=16


Now, let's look at some examples with variables:

X+5 X + 5

Xโˆ’Y X-Y

Aร—12 A\times\frac{1}{2}

X2+6 X^2+6

In this case, the examples include numbers, unknown variables (represented by letters), and mathematical operations (addition, subtraction, multiplication, division, etc.).


Exercises: Variables in Algebraic Expressions

Exercise 1

Find the algebraic expression that corresponds to the number of squares in the nth figure.

algebraic expressions corresponding to the number of squares

Solution:

Numbers of squares n

The first figure is formed from 11 square.

The second figure is formed from 44 squares, which can be expressed as 22 by 22.

The third figure is formed from 99 squares, which can be represented as 33 by 33.

Following this pattern, we can work out that the nth figure will be formed from nร—n=n2 n \times n = nยฒ squares.

Answer:

n2nยฒ


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Exercise 2

Find the algebraic expression that describes the number of circles in the figure n n .

Exercise 2 Assignment

Solution:

In figure 1 (n=1) (n=1) there are 6โˆ’1=56-1= 5 circles.

In figure 2 (n=2) (n=2) there are 6โˆ’2=46-2=4 circles.

In figure 3 (n=3) (n=3) there are 6โˆ’3=36-3=3 circles.

In figure 4 (n=4) (n=4) there are 6โˆ’4=26-4=2 circles.

Following this pattern, we can work out that there will be 6โˆ’n 6-n circles in the nth figure.

Answer:

6โˆ’n 6-n


Exercise 3

Simplify the following expression:

35m+9nโˆ’48m+52n 35m+9n-48m+52n

Solution:

35m+9nโˆ’48m+52n= 35m+9n-48m+52n=

First, we group like terms together.

35mโˆ’48m+9n+52n= 35m-48m+9n+52n=

Then, simplify m m .

โˆ’13m+9n+52n= -13m+9n+52n=

Finally, simplify n n .

โˆ’13m+61n= -13m+61n=

61nโˆ’13m 61n-13m

Answer:

61nโˆ’13m 61n-13m


Do you know what the answer is?

Exercise 4

Simplify the following expression:

47x+57y+34x+89y\frac{4}{7}x+\frac{5}{7}y+\frac{3}{4}x+\frac{8}{9}y

Solution:

The like terms are grouped together and the fraction operations are performed.

47x+34x+57y+89y= \frac{4}{7}x+\frac{3}{4}x+\frac{5}{7}y+\frac{8}{9}y=

4ร—4+3ร—77ร—4x+5ร—9+7ร—87ร—9y= \frac{4\times4+3\times7}{7\times4}x+\frac{5\times9+7\times8}{7\times9}y=

16+2128x+45+5668y= \frac{16+21}{28}x+\frac{45+56}{68}y=

3728x+10168y= \frac{37}{28}x+\frac{101}{68}y=

1928x+13868y 1\frac{9}{28}x+1\frac{38}{68}y

Answer:

1928x+13868y 1\frac{9}{28}x+1\frac{38}{68}y


Exercise 5

Simplify the expression:

3baโ‹…138a+58b+418m+910a+23m 3\frac{b}{a}\cdot1\frac{3}{8}a+\frac{5}{8}b+\frac{4}{18}m+\frac{9}{10}a+\frac{2}{3}m

Solution:

Here, the multiplication is performed and then the like terms are simplified.

3baโ‹…138a+58b+418m+910a+23m 3\frac{b}{a}\cdot1\frac{3}{8}a+\frac{5}{8}b+\frac{4}{18}m+\frac{9}{10}a+\frac{2}{3}m

=2baโ‹…(8+3)8a+88b+910a+418m+23m =\frac{2b}{a}\cdot\frac{\left(8+3\right)}{8}a+\frac{8}{8}b+\frac{9}{10}a+\frac{4}{18}m+\frac{2}{3}m

=3โ‹…118โ‹…a+58b+910a+4+2โ‹…618m =\frac{3\cdot11}{8\cdot a}+\frac{5}{8}b+\frac{9}{10}a+\frac{4+2\cdot6}{18}m

=338b+58b+910a+1618m =\frac{33}{8}b+\frac{5}{8}b+\frac{9}{10}a+\frac{16}{18}m

=33+58b+910a+89m=388b+910a+89m =\frac{33+5}{8}b+\frac{9}{10}a+\frac{8}{9}m=\frac{38}{8}b+\frac{9}{10}a+\frac{8}{9}m

=434b+910a+89m =4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m

Answer:

=434b+910a+89m =4\frac{3}{4}b+\frac{9}{10}a+\frac{8}{9}m


Check your understanding

Review Questions

What is a 'variable' in mathematics?

A variable is an unknown number.


How is a variable represented?

Variables are represented by a symbol, usually a letter of the alphabet such as XX or YY although Greek letters are also often used.


Are there any other names for variables?

Yes, sometimes they are also referred to as 'unknowns' or 'literals'.


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On the Tutorela website you will find a variety of other useful mathematics articles!


How many exercises should I practice?

Since each student learns at a different pace, the answer to this question depends on you.
The important thing is that you are aware of your level and therefore whether or not you need to practice the formulas more.
That said, it is recommended that you do 10 basic and intermediate level exercises in order to learn a single basic formula.


Do you think you will be able to solve it?

Examples with solutions for Variables and Algebraic Expressions

Exercise #1

3x+4x+7+2=? 3x+4x+7+2=\text{?}

Video Solution

Step-by-Step Solution

Let's simplify the expression 3x+4x+7+2 3x + 4x + 7 + 2 step-by-step:

  • Step 1: Combine Like Terms Involving x x
    The terms 3x 3x and 4x 4x are like terms because both involve the variable x x . To combine them, add their coefficients:
    3x+4x=(3+4)x=7x 3x + 4x = (3 + 4)x = 7x

  • Step 2: Combine Constant Terms
    The expression includes constant terms 7 7 and 2 2 . These can be added together to simplify:
    7+2=9 7 + 2 = 9

  • Step 3: Write the Simplified Expression
    Now, combine the results from Step 1 and Step 2 to form the final simplified expression:
    7x+9 7x + 9

Therefore, the simplified expression is 7x+9 7x + 9 .

Reviewing the choices provided, the correct choice is:

  • Choice 2: 7x+9 7x + 9

This matches our simplified expression, confirming our solution is correct.

Answer

7x+9 7x+9

Exercise #2

3z+19zโˆ’4z=? 3z+19z-4z=\text{?}

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Combine like terms by identifying and adding their coefficients.
  • Step 2: Simplify the expression.
  • Step 3: Verify the resulting expression with the provided choices.

Let's work through each step:

Step 1: Identify the coefficients in the expression 3z+19zโˆ’4z 3z + 19z - 4z . The coefficients are 3 3 , 19 19 , and โˆ’4 -4 .

Step 2: Add and subtract these coefficients: 3+19โˆ’4 3 + 19 - 4 .

Step 3: Calculate: 3+19=22 3 + 19 = 22 and then 22โˆ’4=18 22 - 4 = 18 .

Therefore, the simplified expression is 18z 18z .

The solution to the problem is 18z 18z .

Answer

18z 18z

Exercise #3

11+5xโˆ’2x+8= 11+5x-2x+8=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the like terms in the expression.
  • Step 2: Combine the constant terms.
  • Step 3: Combine the coefficients of xx.

Now, let's work through each step:
Step 1: The given expression is 11+5xโˆ’2x+811 + 5x - 2x + 8. There are constants (11 and 8) and terms with xx (5x and -2x).
Step 2: Combine the constants: 11+8=1911 + 8 = 19.
Step 3: Combine the coefficients of xx: 5xโˆ’2x=3x5x - 2x = 3x.

After simplification, the expression becomes 19+3x19 + 3x.

The correct solution from the multiple-choice options is 19+3x\boxed{19 + 3x}.

Answer

19+3X

Exercise #4

5+0+8xโˆ’5= 5+0+8x-5=

Video Solution

Step-by-Step Solution

To simplify the expression 5+0+8xโˆ’55 + 0 + 8x - 5, follow these steps:

  • Step 1: Identify and group like terms. In this case, there are constants (5, 0, -5) and a term with a variable (8x).
  • Step 2: Combine the constants: 5+0โˆ’55 + 0 - 5.
  • Step 3: Calculate: 5โˆ’5=05 - 5 = 0.

Now, our expression simplifies to 0+8x0 + 8x, which is simply 8x8x.

Therefore, the simplified expression is 8x8x.

Answer

8X 8X

Exercise #5

5+8โˆ’9+5xโˆ’4x= 5+8-9+5x-4x=

Video Solution

Step-by-Step Solution

To solve this problem, we will simplify the expression 5+8โˆ’9+5xโˆ’4x5+8-9+5x-4x by separately combining the constants and the variable terms.

Step 1: Simplify the constant terms.
5+8โˆ’9=45 + 8 - 9 = 4

Step 2: Simplify the variable terms.
5xโˆ’4x=x5x - 4x = x

Step 3: Combine the results from steps 1 and 2.
Thus, the simplified expression is 4+x4 + x.

Therefore, the solution to the problem is 4+x4 + x, which corresponds to choice .

Answer

4+X

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