Solve the Fraction Equation: Finding the Numerator in ?/(25x^4-5x^2) = 3/(5x^2)

Complete the corresponding expression in the numerator

?25x45x2=35x2 \frac{?}{25x^4-5x^2}=\frac{3}{5x^2}

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the appropriate numerator
00:04 Let's factor 25 into factors 5 and 3, and 4 squared twice
00:18 Let's mark the common factors
00:22 Let's take out the common factors from the parentheses
00:38 We want to isolate the numerator, so we'll multiply by the denominator
01:00 Let's properly open the parentheses, multiply by each factor
01:16 Let's calculate the products
01:22 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the corresponding expression in the numerator

?25x45x2=35x2 \frac{?}{25x^4-5x^2}=\frac{3}{5x^2}

2

Step-by-step solution

Let's examine the following problem:

?25x45x2=35x2 \frac{?}{25x^4-5x^2}=\frac{3}{5x^2}

Note that in the denominator of the fraction on the left side there is an expression that can be factored using factoring out a common factor. Hence we will factor out the largest possible common factor (meaning that the expression left in parentheses cannot be further factored by taking out a common factor):

?25x45x2=35x2?5x2(5x21)=35x2 \frac{?}{25x^4-5x^2}=\frac{3}{5x^2} \\ \downarrow\\ \frac{?}{5x^2(5x^2-1)}=\frac{3}{5x^2} \\ In factoring, we used of course the law of exponents:

am+n=aman \bm{a^{m+n}=a^m\cdot a^n}

Let's continue solving the problem. Remember the fraction reduction operation. Note that in the fraction's denominator both on the right side and on the left side there is the expression:5x2 5x^2 Therefore we don't want it to be reduced from the denominator on the left side. However, the expression:

5x21 5x^2-1 ,

is not found in the denominator on the right side (which is the fraction after reduction) Therefore we can conclude that this expression needs to be reduced from the denominator on the left side,

Additionally, let's consider the number 3 which appears in the numerator on the right side (which is the fraction after reduction) but is not found in the numerator on the left side, meaning - we want it to be included in choosing the missing expression (which is the product of the desired expressions - in order to obtain the fraction on the right side after reduction)

Therefore the missing expression must be none other than:

3(5x21) 3(5x^2-1)

Let's verify that from this choice we obtain the expression on the right side: (reduction sign)

?5x2(5x21)=35x23(5x21)5x2(5x21)=?35x235x2=!35x2 \frac{?}{5x^2(5x^2-1)}=\frac{3}{5x^2} \\ \downarrow\\ \frac{\textcolor{red}{3(5x^2-1)}}{5x^2(5x^2-1)}\stackrel{?}{= }\frac{3}{5x^2} \\ \downarrow\\ \boxed{\frac{3}{5x^2} \stackrel{!}{= }\frac{3}{5x^2} }

Therefore choosing the expression:

3(5x21) 3(5x^2-1)

is indeed correct.

From opening the parentheses (using the distributive law) we can identify that the correct answer is answer A.

3

Final Answer

15x23 15x^2-3

Practice Quiz

Test your knowledge with interactive questions

Determine if the simplification shown below is correct:

\( \frac{7}{7\cdot8}=8 \)

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Factorization questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations