Solve the Equation: 2log(x+4) = 1 | Step-by-Step Solution

Question

Calculate X:

2log(x+4)=1 2\log(x+4)=1

Video Solution

Solution Steps

00:00 Find X
00:03 We'll use the logarithm of power formula, and move the 2 to the logarithm
00:13 A logarithm without a base is a logarithm with base 10
00:30 We'll use the definition of logarithm to find the solution
00:50 We'll expand brackets using short multiplication formulas
00:55 Let's arrange the equation
01:05 We'll use the roots formula to find possible solutions
01:15 Let's calculate and solve
02:05 And this is the solution to the question

Step-by-Step Solution

To solve the equation 2log(x+4)=1 2\log(x+4) = 1 , we follow these steps:

  • Step 1: Divide both sides by 2 to simplify the equation.
  • Step 2: Apply the logarithm property to rewrite the equation.
  • Step 3: Convert the logarithmic equation into an exponential equation.
  • Step 4: Solve the resulting equation for x x .

Let's work through the steps:

Step 1: Start by dividing both sides of the equation by 2:

log(x+4)=12 \log(x+4) = \frac{1}{2}

Step 2: Translate the logarithmic equation to its exponential form. Recall that logb(A)=C\log_b(A) = C implies bC=Ab^C = A. Here, the base is 10 (since it's a common logarithm when the base is not specified):

x+4=1012 x+4 = 10^{\frac{1}{2}}

Step 3: Simplify 1012 10^{\frac{1}{2}} which is the square root of 10:

x+4=10 x+4 = \sqrt{10}

Step 4: Solve for x x by isolating it:

x=104 x = \sqrt{10} - 4

Thus, the value of x x is 4+10 -4 + \sqrt{10} .

Answer

4+10 -4+\sqrt{10}