Solve the Parabola Inequality: y = -x²- 5x When f(x) < 0

Quadratic Inequalities with Sign Analysis

Look at the following function:

y=x25x y=-x^2-5x

Determine for which values of x x the following is true:

f(x)<0 f\left(x\right) < 0

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the following function:

y=x25x y=-x^2-5x

Determine for which values of x x the following is true:

f(x)<0 f\left(x\right) < 0

2

Step-by-step solution

To determine where the function y=x25x y = -x^2 - 5x is negative, follow these steps:

  • Step 1: Find the roots of the equation x25x=0 -x^2 - 5x = 0 .
  • Step 2: Factor the equation: x(x+5)=0 -x(x + 5) = 0 .
  • Step 3: Solve for x x :
    • x=0 x = 0
    • x=5 x = -5
  • Step 4: Analyze the sign of the quadratic function in the intervals determined by the roots:
    • Interval 1: x<5 x < -5
    • Interval 2: 5<x<0 -5 < x < 0
    • Interval 3: x>0 x > 0

Consider an example point in each interval to determine if y y is negative:

  • For x<5 x < -5 , choose x=6 x = -6 :
    y=(6)25(6)=36+30=6 y = -(-6)^2 - 5(-6) = -36 + 30 = -6 , which is negative.
  • For 5<x<0 -5 < x < 0 , choose x=1 x = -1 :
    y=(1)25(1)=1+5=4 y = -(-1)^2 - 5(-1) = -1 + 5 = 4 , which is positive.
  • For x>0 x > 0 , choose x=1 x = 1 :
    y=(1)25(1)=15=6 y = -(1)^2 - 5(1) = -1 - 5 = -6 , which is negative.

Therefore, the intervals where f(x)<0 f(x) < 0 are x<5 x < -5 and x>0 x > 0 .

The correct answer is x>0 x > 0 or x<5 x < -5 .

3

Final Answer

x>0 x > 0 or x<5 x < -5

Key Points to Remember

Essential concepts to master this topic
  • Root Finding: Factor the quadratic to find where it equals zero
  • Sign Testing: Choose test points like x = -6, -1, 1 in each interval
  • Verification: Check that f(-6) = -6 and f(1) = -6 are both negative ✓

Common Mistakes

Avoid these frequent errors
  • Not testing all three intervals between the roots
    Don't assume the parabola is negative everywhere just because it opens downward = missing positive regions! The sign changes at each root. Always test a point in every interval: x < -5, -5 < x < 0, and x > 0.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

Why do I need to find the roots first?

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The roots are where the parabola crosses the x-axis, changing from positive to negative (or vice versa). These are the boundary points that divide the number line into intervals with consistent signs.

How do I know which intervals to test?

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The roots x=5 x = -5 and x=0 x = 0 create three intervals: x<5 x < -5 , 5<x<0 -5 < x < 0 , and x>0 x > 0 . Test one point from each interval.

What if I get confused about the parabola direction?

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Since the coefficient of x2 x^2 is negative (-1), this parabola opens downward. But don't rely on this - always test points to be sure!

Can I use a number line to visualize this?

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Yes! Draw a number line, mark the roots at -5 and 0, then test points in each region. Mark + or - above each interval based on your test results.

Why isn't the answer just between the roots?

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That's a common mistake! Since this parabola opens downward, it's positive between the roots and negative outside them. Always verify with actual calculations.

Do I include the roots x = -5 and x = 0 in my answer?

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No! The question asks for f(x)<0 f(x) < 0 (strictly less than), so the roots where f(x)=0 f(x) = 0 are not included.

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