Solve the following system of equations:
{x−y=52x−3y=8
To solve this system of linear equations using the elimination method, we will follow these steps:
Step 1: Align the equations for elimination.
- Write the equations as they are given:
x−y=5 (Equation 1)
2x−3y=8 (Equation 2)
Step 2: Eliminate one variable.
- Multiply Equation 1 by 2 to align the coefficient of x with that in Equation 2:
2(x−y)=2×5
Thus, the transformed Equation 1 is:
2x−2y=10 (Equation 3)
- Subtract Equation 2 from Equation 3 to eliminate x:
(2x−2y)−(2x−3y)=10−8
This simplifies to:
y=2
Step 3: Solve for the other variable.
- Substitute y=2 into Equation 1 to solve for x.
x−2=5
Solve for x by adding 2 to both sides:
x=7
Therefore, the solution to the system of linear equations is x=7 and y=2.
This solution matches the choice:
x=7,y=2