Examples with solutions for Subtraction: Shapes instead of numbers

Exercise #1

If:

=12 \colorbox{yellow}\\=12

Solve the following subtraction problem:

68= 68- \colorbox{yellow}\\=

Step-by-Step Solution

To solve this problem, let's follow the steps below:

  • Step 1: Identify the value of the yellow shape.
    According to the problem, the value of the yellow shape is 12 12 .
  • Step 2: Substitute this value into the subtraction expression.
    The expression becomes 6812 68 - 12 .
  • Step 3: Perform the subtraction operation.
    Calculate 6812 68 - 12 as follows:

6812=56 68 - 12 = 56

The steps for subtraction are:
Break down 6812 68 - 12 into simpler components:
Subtract the units: 82=6 8 - 2 = 6
Subtract the tens: 61=5 6 - 1 = 5
Combine the results: 56 56

Therefore, the solution to the problem is 56 56 .

The correct choice from the provided options is 56 \boxed{56} .

Answer

56 56

Exercise #2

Determine the numerical value of the triangle:

75=70 75-\triangle=70

Step-by-Step Solution

To solve the equation 75=70 75 - \triangle = 70 , we need to find the value of \triangle.

We start with the equation:

75=70 75 - \triangle = 70

Our goal is to solve for \triangle. To do this, we isolate \triangle by rearranging the equation:

=7570\triangle = 75 - 70

Next, we perform the subtraction on the right side:

=5\triangle = 5

Therefore, the numerical value of the triangle is =5\triangle = 5.

Thus, the correct answer is choice 4: 5 5 .

Answer

5 5

Exercise #3

Determine the numerical value of the triangle:

94=90 94-\triangle=90

Step-by-Step Solution

To solve this problem, follow these steps:

  • Step 1: Understand the given equation 94=9094 - \triangle = 90. We need to find \triangle.
  • Step 2: Move terms to isolate \triangle:
    Rearrange the equation to: =9490\triangle = 94 - 90.
  • Step 3: Perform the subtraction: 9490=494 - 90 = 4.
  • Step 4: Therefore, the value of \triangle is 44.

Thus, the numerical value represented by the triangle is 4 \mathbf{4} .

Answer

4 4

Exercise #4

If:

=7 \circ=7

Solve the following subtraction problem:

69= 69-\circ=

Step-by-Step Solution

To solve this mathematical problem, we utilize the following steps:

  • Step 1: Substitute the value of the symbol \circ into the expression 6969 - \circ.
  • Step 2: Compute the subtraction using the given value.
  • Step 3: Verify the result with the given choices (if applicable).

Let's execute each step:

Step 1: Given that =7\circ = 7, substitute it into the expression: 6969 - \circ.

Step 2: This becomes 69769 - 7. Performing the subtraction:

697=6269 - 7 = 62.

Therefore, the solution to the problem is 62 \boxed{62} .

Answer

62 62

Exercise #5

If

=7 \circ=7

Solve the following subtraction problem:

57= 57-\circ=

Step-by-Step Solution

The problem requires us to solve the equation 57 57 - \circ , where =7 \circ = 7 . Follow these steps:

  • Step 1: Substitute \circ with its given value: =7 \circ = 7 .
  • Step 2: Perform the subtraction using basic arithmetic: 577 57 - 7 .
  • Step 3: Calculate the result: 577=50 57 - 7 = 50 .

Following these steps, the solution to the problem is 50 \boldsymbol{50} .

Answer

50 50

Exercise #6

Determine the numerical value of the triangle:

88=80 88-\triangle=80

Step-by-Step Solution

To solve the problem 88=8088 - \triangle = 80, we will proceed as follows:

  • Step 1: Identify what needs to be solved. We need to find the value of \triangle in the equation.
  • Step 2: Rearrange the equation to solve for \triangle. Start with 88=8088 - \triangle = 80.
  • Step 3: Isolate the triangle by subtracting 80 from 88. This gives us =8880\triangle = 88 - 80.
  • Step 4: Perform the subtraction. Calculate 8880=888 - 80 = 8.

Thus, the value of the triangle, \triangle, is 88.

The correct answer from the provided choices is option : 8 8

Answer

8 8

Exercise #7

Determine the numerical value of the triangle:

If

9=20 \triangle-9=20

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Start with the equation: 9=20 \triangle - 9 = 20
  • Add 9 to both sides to isolate \triangle .

Now, let's carry out these steps:

Starting with the equation 9=20 \triangle - 9 = 20 .
To find \triangle , we add 9 to both sides:
9+9=20+9 \triangle - 9 + 9 = 20 + 9

Simplifying this gives us:
=29 \triangle = 29

Therefore, the numerical value represented by \triangle is 29 \boxed{29} .

Looking at the multiple-choice options, we find that 29 29 matches choice 3.

Answer

29 29

Exercise #8

Determine the numerical value of the triangle:

8=90 \triangle-8=90

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Add 8 to both sides of the equation 8=90 \triangle - 8 = 90 .
  • Step 2: Simplify to determine the value of \triangle .

Now, let's work through each step:

Step 1: Add 8 to both sides of the equation:
8+8=90+8 \triangle - 8 + 8 = 90 + 8

Step 2: Simplify the equation:
=98 \triangle = 98

This means the value of the triangle ( \triangle ) that satisfies the equation is 98 98 .

Therefore, the solution to the problem is 98 98 .

Answer

98 98

Exercise #9

Determine the numerical value of the triangle:

3=70 \triangle-3=70

Step-by-Step Solution

To solve the equation 3=70 \triangle - 3 = 70 , we will use basic algebra to isolate the value of \triangle.

We start by adding 3 to both sides of the equation to isolate \triangle:

3+3=70+3 \triangle - 3 + 3 = 70 + 3

Notice that 3+3 -3 + 3 on the left side simplifies to 0, which leaves us with:

=70+3 \triangle = 70 + 3

Now, perform the arithmetic on the right side:

=73 \triangle = 73

Hence, the numerical value of the triangle is 73 73 .

Answer

73 73

Exercise #10

Determine the numerical value of the triangle:

7=80 \triangle-7=80

Step-by-Step Solution

The problem involves solving a simple algebraic equation:

7=80 \triangle - 7 = 80

  • Step 1: To solve for \triangle , we need to isolate it on one side of the equation. We can do this by adding 7 to both sides of the equation to reverse the subtraction.

7+7=80+7 \triangle - 7 + 7 = 80 + 7

This simplifies to:

=87 \triangle = 87

The value of the triangle symbol \triangle is 87 87 .

Therefore, the solution to the problem is =87 \triangle = 87 , which corresponds to choice 4 in the provided list of answer choices.

Answer

87 87

Exercise #11

If

=8 \circ=8

Solve the following subtraction problem:

57= 57-\circ=

Step-by-Step Solution

To solve this problem, we'll perform a direct replacement and subtraction. Here are the steps:

  • Step 1: Replace \circ with its given value. We know that =8 \circ = 8 , so we substitute to get 578 57 - 8 .
  • Step 2: Perform the subtraction operation. We need to compute 578 57 - 8 .

Starting from the rightmost digit of the two numbers involved, we need to subtract 8 from 57:

  • First, look at the units digit: Since 7 is greater than 8, let's subtract directly: 78 7 - 8 cannot be done directly as we need to regroup.
  • We regroup by borrowing 1 ten from the tens place in 57. This turns the 5 in the tens place into a 4, and the 7 in the units place into 17.
  • Now subtract the single digits: 178=9 17 - 8 = 9 .
  • Finally, subtract the tens digits: 40=4 4 - 0 = 4 .

As a result, 578=49 57 - 8 = 49 .

This solution corresponds to choice 1: 49 49 .

Therefore, the solution to the problem is 49 49 .

Answer

49 49

Exercise #12

If

=9 \colorbox{yellow}\\=9

Solve the following subtraction problem:

68= 68- \colorbox{yellow}\\=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the number represented by the yellow box.
  • Step 2: Perform the subtraction operation.
  • Step 3: Determine the resulting value.

Now, let's work through each step:
Step 1: The problem gives us that the yellow box equals 9.
Step 2: Perform the subtraction operation 689 68 - 9 .
Step 3: Calculating the subtraction, we have 689=59 68 - 9 = 59 .

Therefore, the solution to the problem is 59 59 .

Answer

59 59

Exercise #13

If

=8 \circ=8

Solve the following subtraction problem:

34= 34-\circ=

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Substitute the given value for \circ into the subtraction problem.
  • Step 2: Perform the subtraction.

Now, let's work through each step:

Step 1: We know that =8 \circ = 8 . Substitute this value into the expression:

34 34 - \circ becomes 348 34 - 8 .

Step 2: Perform the subtraction:

348=26 34 - 8 = 26 .

Therefore, the solution to the problem is 26 \boxed{26} .

Answer

26 26

Exercise #14

If

=8 \circ=8

Solve the following subtraction problem:

24= 24-\circ=

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Substitute the value of \circ with 8 8 .
  • Step 2: Perform the subtraction.

Now, let's work through each step:

Step 1: The problem tells us that =8 \circ = 8 .

Step 2: Substitute 8 8 into the equation where \circ appears: 248 24 - 8 .

Step 3: Calculate the result of the subtraction:
Start from 24 and count backward by 8 units:

  • Subtracting 4 from 24 gives us 20.
  • Then, subtracting another 4 from 20 results in 16.

Therefore, the solution to the problem is 16 16 .

Answer

16 16

Exercise #15

If

=7 \colorbox{yellow}\\=7

Solve the following subtraction problem:

62= 62- \colorbox{yellow}\\=

Step-by-Step Solution

To solve this problem, we'll perform a straightforward subtraction operation:

  • Step 1: Set up the subtraction operation using the given numbers:
    62762 - 7.
  • Step 2: Subtract 7 from 62:
    62 minus 7 equals 55.

Therefore, the solution to the problem is 5555.

Given the choices, the correct answer is choice 22, which is 5555.

Answer

55 55

Exercise #16

If:

=7 \colorbox{yellow}\\=7

Solve the following subtraction problem:

81= 81- \colorbox{yellow}\\=

Step-by-Step Solution

To solve this subtraction problem, we'll proceed with the following steps:

  • Step 1: Recognize that the yellow box is equal to 77.
  • Step 2: Replace the yellow box in 81yellow box81 - \text{{yellow box}} with 77.
  • Step 3: Perform the subtraction 81781 - 7.

Let's work through these steps:

Step 1: From the given information, the yellow box is 77.

Step 2: Substitute the yellow box with 77 in the expression.

The expression becomes 81781 - 7.

Step 3: Calculate 81781 - 7. We perform the subtraction:

  • Subtract 77 from 8181:
  • 817=7481 - 7 = 74

The result is 7474.

Therefore, the solution to the problem is 74 74 .

Answer

74 74

Exercise #17

If

=7 \colorbox{yellow}\\=7

Solve the following subtraction problem:

82= 82- \colorbox{yellow}\\=

Step-by-Step Solution

To solve this problem, we'll use the substitution method for the subtraction equation provided:

  • Step 1: Identify the value represented by the symbol. We are given that the yellow box equals 7.
  • Step 2: Substitute the value 7 into the subtraction problem: 82782 - 7.
  • Step 3: Perform the subtraction operation: 827=75 82 - 7 = 75

Therefore, the solution to the problem is 75 75 .

Answer

75 75

Exercise #18

If:

=7 \colorbox{yellow}\\=7

Solve the following subtraction problem:

41= 41- \colorbox{yellow}\\=

Step-by-Step Solution

To solve this problem, we'll proceed with straightforward subtraction:

  • Step 1: Recognize that the yellow box equals 7.
  • Step 2: Set up the subtraction: 417 41 - 7 .
  • Step 3: Perform the subtraction calculation.

Now, let's calculate this step-by-step:
Starting with the minuend 41, subtract the subtrahend 7.
Calculation: 417=34 41 - 7 = 34 .

Therefore, the solution to the subtraction problem is 34 34 .

Answer

34 34