Examples with solutions for Subtraction: Simple subtraction of double digits

Exercise #1

Determine the numerical value of the triangle:

If

9=20 \triangle-9=20

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Start with the equation: 9=20 \triangle - 9 = 20
  • Add 9 to both sides to isolate \triangle .

Now, let's carry out these steps:

Starting with the equation 9=20 \triangle - 9 = 20 .
To find \triangle , we add 9 to both sides:
9+9=20+9 \triangle - 9 + 9 = 20 + 9

Simplifying this gives us:
=29 \triangle = 29

Therefore, the numerical value represented by \triangle is 29 \boxed{29} .

Looking at the multiple-choice options, we find that 29 29 matches choice 3.

Answer

29 29

Exercise #2

Determine the numerical value of the triangle:

8=90 \triangle-8=90

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Add 8 to both sides of the equation 8=90 \triangle - 8 = 90 .
  • Step 2: Simplify to determine the value of \triangle .

Now, let's work through each step:

Step 1: Add 8 to both sides of the equation:
8+8=90+8 \triangle - 8 + 8 = 90 + 8

Step 2: Simplify the equation:
=98 \triangle = 98

This means the value of the triangle ( \triangle ) that satisfies the equation is 98 98 .

Therefore, the solution to the problem is 98 98 .

Answer

98 98

Exercise #3

Determine the numerical value of the triangle:

3=70 \triangle-3=70

Step-by-Step Solution

To solve the equation 3=70 \triangle - 3 = 70 , we will use basic algebra to isolate the value of \triangle.

We start by adding 3 to both sides of the equation to isolate \triangle:

3+3=70+3 \triangle - 3 + 3 = 70 + 3

Notice that 3+3 -3 + 3 on the left side simplifies to 0, which leaves us with:

=70+3 \triangle = 70 + 3

Now, perform the arithmetic on the right side:

=73 \triangle = 73

Hence, the numerical value of the triangle is 73 73 .

Answer

73 73

Exercise #4

Determine the numerical value of the triangle:

7=80 \triangle-7=80

Step-by-Step Solution

The problem involves solving a simple algebraic equation:

7=80 \triangle - 7 = 80

  • Step 1: To solve for \triangle , we need to isolate it on one side of the equation. We can do this by adding 7 to both sides of the equation to reverse the subtraction.

7+7=80+7 \triangle - 7 + 7 = 80 + 7

This simplifies to:

=87 \triangle = 87

The value of the triangle symbol \triangle is 87 87 .

Therefore, the solution to the problem is =87 \triangle = 87 , which corresponds to choice 4 in the provided list of answer choices.

Answer

87 87