Trapezoid Practice Problems for 9th Grade - Area & Properties

Formula for the area of a trapezoid:

$\frac{(base+base)}{2}\times altura$

We substitute the data into the formula and solve:

$\frac{9+12}{2}\times5=\frac{21}{2}\times5=\frac{105}{2}=52.5$

In order to calculate the perimeter of the trapezoid we must add together the measurements of all of its sides:

7+10+7+12 =

36

And that's the solution!

The problem requires calculating the perimeter of the trapezoid by summing the lengths of its sides. Based on the given trapezoid diagram, the side lengths are clearly marked as follows:

• First side: $4$
• Second side: $9$
• Third side: $6$
• Fourth side: $13$

According to the formula for the perimeter of a trapezoid:

$P = a + b + c + d$

Substituting the respective values:

$P = 4 + 9 + 6 + 13$

Calculating the sum, we find:

$P = 32$

Thus, the perimeter of the trapezoid is $32$.

First, we need to remind ourselves of how to work out the area of a trapezoid:

$\frac{(Base+Base)\cdot h}{2}=Area$

Now let's substitute the given data into the formula:

(10+6)*5 =
2

Let's start with the upper part of the equation:

16*5 = 80

80/2 = 40

First, let's remind ourselves of the formula for the area of a trapezoid:

$A=\frac{\left(Base\text{ }+\text{ Base}\right)\text{ h}}{2}$

We substitute the given values into the formula:

(2.5+4)*6 =
6.5*6=
39/2 = 
19.5