Calculate √5 × √6: Multiplying Square Roots Step-by-Step

Radical Multiplication with Product Property

Solve the following exercise:

56= \sqrt{5}\cdot\sqrt{6}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 The square root of a number (A) multiplied by the square root of another number (B)
00:07 equals the square root of their product (A times B)
00:11 Apply this formula to our exercise and proceed to calculate the product
00:15 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

56= \sqrt{5}\cdot\sqrt{6}=

2

Step-by-step solution

In order to simplify the given expression, apply two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}}

b. The law of exponents for exponents applied to terms in parentheses (in reverse):

xnyn=(xy)n x^n\cdot y^n =(x\cdot y)^n

Begin by converting the square roots to exponents using the law of exponents mentioned in a':

56=512612= \sqrt{5}\cdot\sqrt{6}= \\ \downarrow\\ 5^{\frac{1}{2}}\cdot6^{\frac{1}{2}}=

Due to the fact that there is multiplication between two terms with identical exponents, we are able to apply the law of exponents mentioned in b' and then proceed to combine them together inside of parentheses, raised to the same exponent:

512612=(56)12=3012=30 5^{\frac{1}{2}}\cdot6^{\frac{1}{2}}= \\ (5\cdot6)^{\frac{1}{2}}=\\ 30^{\frac{1}{2}}=\\ \boxed{\sqrt{30}}

In the final steps, we performed the multiplication within the parentheses and again used the definition of root as an exponent mentioned in a' (in reverse) to return to root notation.

Therefore, the correct answer is answer d.

3

Final Answer

30 \sqrt{30}

Key Points to Remember

Essential concepts to master this topic
  • Product Rule: ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} when both radicands are positive
  • Technique: Convert to exponents: 56=512612=(56)12 \sqrt{5} \cdot \sqrt{6} = 5^{\frac{1}{2}} \cdot 6^{\frac{1}{2}} = (5 \cdot 6)^{\frac{1}{2}}
  • Check: Verify 30 \sqrt{30} by calculating (30)2=30 (\sqrt{30})^2 = 30

Common Mistakes

Avoid these frequent errors
  • Adding the numbers under the radicals instead of multiplying
    Don't think 56=5+6=11 \sqrt{5} \cdot \sqrt{6} = \sqrt{5+6} = \sqrt{11} ! This confuses addition with multiplication and gives a completely wrong answer. Always multiply the radicands: 56=5×6=30 \sqrt{5} \cdot \sqrt{6} = \sqrt{5 \times 6} = \sqrt{30} .

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why can I multiply the numbers under the square roots together?

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This works because of the product property of radicals: ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} . Think of it like this - when you have the same type of root (both square roots), you can combine what's underneath!

Should I try to simplify 30 \sqrt{30} further?

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Let's check! To simplify 30 \sqrt{30} , look for perfect square factors. Since 30 = 2 × 3 × 5 and none of these repeat, 30 \sqrt{30} is already in simplest form.

Can I use this rule with other types of roots, like cube roots?

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Yes! The product property works for any matching roots: a3b3=ab3 \sqrt[3]{a} \cdot \sqrt[3]{b} = \sqrt[3]{a \cdot b} . Just make sure the index numbers (the little numbers) are the same!

What if one of the numbers under the square root is negative?

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Be careful! This product rule only works when both numbers under the radicals are positive. With negative numbers, you need to use imaginary numbers, which is a more advanced topic.

How do I remember not to add the numbers instead of multiply?

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Remember: multiplication outside means multiplication inside! When you see 56 \sqrt{5} \cdot \sqrt{6} , the × symbol tells you to multiply 5 and 6 under one radical sign.

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