Solve Square Root Multiplication: √1 × √25

While that works for perfect squares like this problem, it won't work for expressions like $\sqrt{2} \cdot \sqrt{8}$. The product property $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ is the universal method that always works!

Use the same product property! For example: $\sqrt{2} \cdot \sqrt{8} = \sqrt{16} = 4$. The product inside might become a perfect square even when the original numbers aren't.

No! Square root multiplication is commutative, so $\sqrt{1} \cdot \sqrt{25} = \sqrt{25} \cdot \sqrt{1}$. You can multiply in any order.

A perfect square is a whole number that equals another whole number squared. Common ones to memorize: $1=1^2, 4=2^2, 9=3^2, 16=4^2, 25=5^2, 36=6^2$, etc.

The same rule applies! $\sqrt{a} \cdot \sqrt{b} \cdot \sqrt{c} = \sqrt{a \cdot b \cdot c}$. Just multiply all the numbers under one big square root.