Multiply Square Roots: Calculate √3 × √3

Square Root Multiplication with Same Radicands

Solve the following exercise:

33= \sqrt{3}\cdot\sqrt{3}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 The root of a number (A) multiplied by the root of another number (B)
00:07 equals the root of their product (A times B)
00:10 Apply this formula to our exercise, and calculate the product
00:15 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

33= \sqrt{3}\cdot\sqrt{3}=

2

Step-by-step solution

In order to simplify the given expression, we will use two laws of exponents:

a. The definition of a root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}} b. The law of exponents for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's start by converting the square roots to exponents using the law mentioned in a:

33=312312= \sqrt{3}\cdot\sqrt{3}= \\ \downarrow\\ 3^{\frac{1}{2}}\cdot3^{\frac{1}{2}}= Let's continue, notice that we got a number multiplied by itself, therefore, according to the definition of exponents we can write the expression we got as a power of that same number, then we'll use the law of exponents mentioned in b and perform the exponentiation of the term in parentheses:

312312=(312)2=3122=31=3 3^{\frac{1}{2}}\cdot3^{\frac{1}{2}}= \\ (3^{\frac{1}{2}})^2=\\ 3^{\frac{1}{2}\cdot2}=\\ 3^1=\\ \boxed{3} Additionally, we identify that:

3=9 3=\sqrt{9} Therefore, the correct answer (most accurate) is answer d.

3

Final Answer

Answers a + b

Key Points to Remember

Essential concepts to master this topic
  • Rule: When multiplying identical square roots, aa=a \sqrt{a} \cdot \sqrt{a} = a
  • Technique: Convert to exponents: 33=31/231/2=31=3 \sqrt{3} \cdot \sqrt{3} = 3^{1/2} \cdot 3^{1/2} = 3^1 = 3
  • Check: Verify that 3×3=9 3 \times 3 = 9 , so 9=3 \sqrt{9} = 3 confirms our answer ✓

Common Mistakes

Avoid these frequent errors
  • Adding square roots instead of multiplying
    Don't think 33=3+3=6 \sqrt{3} \cdot \sqrt{3} = \sqrt{3+3} = \sqrt{6} ! This confuses addition with multiplication and gives a completely wrong result. Always remember that multiplying identical square roots gives you the number under the radical: aa=a \sqrt{a} \cdot \sqrt{a} = a .

Practice Quiz

Test your knowledge with interactive questions

Choose the largest value

FAQ

Everything you need to know about this question

Why does 3×3 \sqrt{3} \times \sqrt{3} equal 3 and not 9?

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Think of it this way: 3 \sqrt{3} means "what number times itself gives 3?" So when you multiply 3×3 \sqrt{3} \times \sqrt{3} , you get that original number back, which is 3!

Can I use the multiplication property ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} ?

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Yes! Using this property: 33=3×3=9=3 \sqrt{3} \cdot \sqrt{3} = \sqrt{3 \times 3} = \sqrt{9} = 3 . Both methods give the same answer.

What's the difference between 9 \sqrt{9} and 9 as answers?

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9 \sqrt{9} and 3 are exactly the same value since 9=3 \sqrt{9} = 3 . However, 3 is the simplified form, which is what we want as our final answer.

How do I remember this rule for tests?

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Remember: "Square root times itself = the inside number". Practice with simple examples like 4×4=4 \sqrt{4} \times \sqrt{4} = 4 and 5×5=5 \sqrt{5} \times \sqrt{5} = 5 .

What if the square roots are different, like 2×3 \sqrt{2} \times \sqrt{3} ?

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When the radicands are different, use ab=ab \sqrt{a} \cdot \sqrt{b} = \sqrt{ab} . So 2×3=6 \sqrt{2} \times \sqrt{3} = \sqrt{6} , which cannot be simplified further.

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