Calculate Deltoid Dimensions: Finding DB When AC = 2X and Area = 32 cm²

Question

Shown below is the deltoid ABCD.

AC = 2X

DB = X

The area of the deltoid is equal to 32 cm².

Calculate DB.

S=32S=32S=322X2X2XXXXAAABBBCCCDDD

Video Solution

Solution Steps

00:11 Let's start by calculating the diagonal D to B.
00:15 We'll use the formula for finding a rhombus's area.
00:20 That's diagonal one times diagonal two, divided by two.
00:25 Let's substitute the given values to find diagonal D to B.
00:33 Then, multiply by two to remove the fraction.
00:43 Next, we'll isolate the variable X.
00:56 And that's how we solve this problem!

Step-by-Step Solution

To solve this problem, we will utilize the formula for the area of a deltoid, which is 12×AC×DB \frac{1}{2} \times AC \times DB . Given:

  • Diagonal AC=2X AC = 2X
  • Diagonal DB=X DB = X
  • Area = 32cm2 32 \, \text{cm}^2

The formula for the area of the deltoid is:

Area=12×AC×DB \text{Area} = \frac{1}{2} \times AC \times DB

Substitute the given values into the formula:

32=12×2X×X 32 = \frac{1}{2} \times 2X \times X

Simplify the equation:

32=12×2X2 32 = \frac{1}{2} \times 2X^2

32=X2 32 = X^2

Solve for X X by taking the square root of both sides:

X=32 X = \sqrt{32}

Since DB=X DB = X , the length of diagonal DB DB is 32\sqrt{32} .

Thus, the solution to the problem is 32\sqrt{32}.

Answer

32 \sqrt{32}