Calculate the Descending Area of f(x) = (1/2)x²: Quadratic Function Analysis

Find the descending area of the function

f(x)=12x2 f(x)=\frac{1}{2}x^2

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Step-by-step video solution

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00:00 Find the domain of decrease of the function
00:03 Notice the coefficient of X squared is positive, so the function is concave up
00:07 Let's look at the trinomial coefficients
00:15 Use the formula to find the vertex of the parabola
00:21 Substitute appropriate values according to the given data and solve to find the vertex
00:24 This is the X value at the vertex of the parabola
00:29 Determine when the parabola decreases and increases based on its type
00:33 Draw the X-axis and find the domain of decrease
00:42 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Find the descending area of the function

f(x)=12x2 f(x)=\frac{1}{2}x^2

2

Step-by-step solution

To solve the problem of finding the descending area of the function f(x)=12x2 f(x) = \frac{1}{2}x^2 , we follow these steps:

  • Step 1: Calculate the derivative of the given function. The function is f(x)=12x2 f(x) = \frac{1}{2}x^2 . Differentiating this, we get f(x)=ddx(12x2)=x f'(x) = \frac{d}{dx}(\frac{1}{2}x^2) = x .
  • Step 2: Determine where the derivative is negative. Since f(x)=x f'(x) = x , the derivative is negative when x<0 x < 0 .
  • Step 3: Conclude the solution. We find that the function f(x) f(x) is decreasing for x<0 x < 0 .

Thus, the descending area (domain where the function is decreasing) for the function f(x)=12x2 f(x) = \frac{1}{2}x^2 is x<0 x < 0 .

The correct choice that matches this solution is: x<0 x < 0 .

3

Final Answer

x<0 x < 0

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\( y=-6x^2 \)

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