ABCD is a parallelogram whose perimeter is equal to 22 cm.
Side AB is smaller by 5 than side AD
The height of the parallelogram for the side AD is 2 cm
What is the area of the parallelogram?
ABCD is a parallelogram whose perimeter is equal to 22 cm.
Side AB is smaller by 5 than side AD
The height of the parallelogram for the side AD is 2 cm
What is the area of the parallelogram?
To solve this problem, we will follow these steps:
Let's begin:
Step 1: Calculate side lengths
Given that the perimeter is 22 cm, we have:
\begin{equation} 2(AB + AD) = 22 \end{equation}The equation simplifies to:
\begin{equation} AB + AD = 11 \end{equation}We are also given:
\begin{equation} AB = AD - 5 \end{equation}Substitute this in the first equation:
\begin{equation} (AD - 5) + AD = 11 \end{equation} \begin{equation} 2AD - 5 = 11 \end{equation} \begin{equation} 2AD = 16 \end{equation} \begin{equation} AD = 8 \end{equation}Now, substitute back into the expression for :
\begin{equation} AB = 8 - 5 = 3 \end{equation}Step 2: Calculate the area
With cm as the base (since the problem specifies height to ) and the given height of 2 cm, the area is calculated as:
\begin{equation} A = \text{base} \times \text{height} = 8 \times 2 = 16 \, \text{cm}^2 \end{equation}Therefore, the area of the parallelogram is 16 cm².
16 cm²