Convert the Function f(x)=(x-2)²+3 to its Standard Form

Quadratic Functions with Vertex to Standard Form

Find the standard representation of the following function

f(x)=(x2)2+3 f(x)=(x-2)^2+3

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Step-by-step video solution

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00:00 Simplified to the standard representation of the function
00:03 Open parentheses according to the shortened multiplication formulas
00:12 Calculate powers and products
00:19 Add
00:25 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the standard representation of the following function

f(x)=(x2)2+3 f(x)=(x-2)^2+3

2

Step-by-step solution

To convert the function from vertex form to standard form, follow these steps:

  • Step 1: Identify the vertex form - f(x)=(x2)2+3 f(x) = (x-2)^2 + 3 . The terms inside the parentheses represent a perfect square trinomial.
  • Step 2: Expand the square. Recall: (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 . Here, a=x a = x and b=2 b = 2 .
  • Step 3: Expand (x2)2(x-2)^2:
    (x2)2=x22x2+22=x24x+4 (x-2)^2 = x^2 - 2 \cdot x \cdot 2 + 2^2 = x^2 - 4x + 4 .
  • Step 4: Add the constant from the original function:
    f(x)=(x24x+4)+3=x24x+7 f(x) = (x^2 - 4x + 4) + 3 = x^2 - 4x + 7 .

After expanding and simplifying, we find that f(x)=x24x+7 f(x) = x^2 - 4x + 7 is the standard form of the function.

Therefore, the correct choice that matches this solution is choice 3, which is f(x)=x24x+7 f(x) = x^2 - 4x + 7 .

3

Final Answer

f(x)=x24x+7 f(x)=x^2-4x+7

Key Points to Remember

Essential concepts to master this topic
  • Expansion Rule: Use (a-b)² = a² - 2ab + b² formula
  • Technique: (x-2)² = x² - 4x + 4, then add constant term
  • Check: Standard form ax² + bx + c should equal original when factored ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to add the constant term after expanding
    Don't expand (x-2)² = x² - 4x + 4 and stop there = missing the +3! This gives x² - 4x + 4 instead of x² - 4x + 7. Always add all constant terms outside the parentheses after expanding.

Practice Quiz

Test your knowledge with interactive questions

Create an algebraic expression based on the following parameters:

\( a=3,b=0,c=-3 \)

FAQ

Everything you need to know about this question

What's the difference between vertex form and standard form?

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Vertex form is f(x) = a(x-h)² + k and shows the vertex clearly at (h,k). Standard form is f(x) = ax² + bx + c and makes it easier to identify the y-intercept and use the quadratic formula.

Why do I need to expand (x-2)²?

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Expanding lets you see all the terms clearly! (x2)2 (x-2)^2 hides the middle term -4x that becomes visible when you expand to x24x+4 x^2 - 4x + 4 .

How do I remember the (a-b)² formula?

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Think "First squared, minus twice the product, plus second squared": (x2)2=x22(x)(2)+22=x24x+4 (x-2)^2 = x^2 - 2(x)(2) + 2^2 = x^2 - 4x + 4

What if I get the wrong constant term?

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Double-check your arithmetic! From (x2)2+3 (x-2)^2 + 3 , you get x24x+4+3 x^2 - 4x + 4 + 3 . Make sure to add: 4 + 3 = 7.

Can I check my answer by plugging in a value?

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Absolutely! Try x = 0: Original gives (02)2+3=4+3=7 (0-2)^2 + 3 = 4 + 3 = 7 . Your standard form should give 024(0)+7=7 0^2 - 4(0) + 7 = 7

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