Express (x-6)² + 2x in Standard Function Form

Expanding Quadratics with Linear Terms

Find the standard representation of the following function

f(x)=(x6)2+2x f(x)=(x-6)^2+2x

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Step-by-step video solution

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00:00 Simplify to the standard representation of the function
00:03 Expand brackets using shortened multiplication formulas
00:08 Calculate powers and products
00:18 Group factors
00:30 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the standard representation of the following function

f(x)=(x6)2+2x f(x)=(x-6)^2+2x

2

Step-by-step solution

To solve this problem, we'll transform the given expression into standard quadratic form by expanding and simplifying:

  • Step 1: Expand (x6)2 (x - 6)^2
    (x6)2=x212x+36 (x - 6)^2 = x^2 - 12x + 36
  • Step 2: Add 2x 2x
    f(x)=x212x+36+2x f(x) = x^2 - 12x + 36 + 2x
  • Step 3: Simplify
    Combine like terms: 12x+2x=10x-12x + 2x = -10x, resulting in the expression:
    f(x)=x210x+36 f(x) = x^2 - 10x + 36

Therefore, the standard form of the function f(x) f(x) is x210x+36 x^2 - 10x + 36 . This corresponds to choice 1 in the given list.

Thus, the final solution is f(x)=x210x+36 f(x) = x^2 - 10x + 36 .

3

Final Answer

f(x)=x210x+36 f(x)=x^2-10x+36

Key Points to Remember

Essential concepts to master this topic
  • Rule: Expand perfect squares using (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2
  • Technique: (x6)2=x212x+36 (x-6)^2 = x^2 - 12x + 36 then add 2x 2x
  • Check: Combine like terms: 12x+2x=10x -12x + 2x = -10x gives x210x+36 x^2 - 10x + 36

Common Mistakes

Avoid these frequent errors
  • Incorrectly expanding the perfect square
    Don't write (x6)2=x2+36 (x-6)^2 = x^2 + 36 forgetting the middle term = wrong final answer! This misses the crucial 2(x)(6)=12x -2(x)(6) = -12x term from the perfect square formula. Always use (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 completely.

Practice Quiz

Test your knowledge with interactive questions

Create an algebraic expression based on the following parameters:

\( a=3,b=0,c=-3 \)

FAQ

Everything you need to know about this question

How do I remember the perfect square formula?

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Think of it as FOIL with identical binomials! (x6)2=(x6)(x6) (x-6)^2 = (x-6)(x-6) . First: xx=x2 x \cdot x = x^2 , Outer + Inner: 6x+(6x)=12x -6x + (-6x) = -12x , Last: (6)(6)=36 (-6)(-6) = 36 .

Why do I get different answers when I don't combine like terms?

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Standard form requires all like terms combined! If you leave x212x+36+2x x^2 - 12x + 36 + 2x as is, it's not simplified. Always combine 12x+2x=10x -12x + 2x = -10x to get the final answer.

Can I expand this differently?

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You could use distribution twice: (x6)(x6) (x-6)(x-6) then FOIL, but the perfect square formula (ab)2=a22ab+b2 (a-b)^2 = a^2 - 2ab + b^2 is faster and less error-prone!

What if I forget to add the 2x term?

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You'll get x212x+36 x^2 - 12x + 36 instead of the correct x210x+36 x^2 - 10x + 36 ! Always read the entire expression carefully and don't miss any terms.

How do I check my final answer?

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Substitute a simple value like x=0 x = 0 into both forms. Original: (06)2+2(0)=36 (0-6)^2 + 2(0) = 36 . Your answer: 0210(0)+36=36 0^2 - 10(0) + 36 = 36 . They match!

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