Deltoid Geometry: Calculate OC Given AO = 3cm and Triangle Ratio 1:3

Deltoid Area Ratios with Proportional Segments

Shown below is the deltoid ABCD.

The ratio between triangle ABD and triangle BDC is 1:3.

Given in cm:

AO = 3

Calculate side OC.

333AAABBBCCCDDDOOO

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:11 Let's find the length of OC.
00:14 First, we'll use the formula to calculate the area of triangle A, B, D.
00:24 Next, we'll do the same for triangle B, D, C.
00:31 Now, let's substitute these area formulas into the ratio given in the problem.
00:41 We'll simplify everything where possible.
00:52 Using the information from the problem, we know the size of A, O.
00:57 We'll use this to find the value of C, O.
01:02 And that's how we solve this problem! Great job working through it!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Shown below is the deltoid ABCD.

The ratio between triangle ABD and triangle BDC is 1:3.

Given in cm:

AO = 3

Calculate side OC.

333AAABBBCCCDDDOOO

2

Step-by-step solution

To solve for OCOC, follow these steps:

  • Step 1: Establish the area relationships. Given Area of ABDArea of BDC=13 \frac{\text{Area of } \triangle ABD}{\text{Area of } \triangle BDC} = \frac{1}{3} , these areas are proportional to segments AOAO and OCOC under height implications.
  • Step 2: Apply the area ratio property. Since areas are directly proportional to their corresponding triangle heights from a shared vertex, AOOC=13 \frac{AO}{OC} = \frac{1}{3} .
  • Step 3: Algebraically solve for OCOC. Expressing proportions, 13×OC=AO\frac{1}{3} \times OC = AO, gives OC=3×3OC = 3 \times 3.
  • Step 4: Solve: OC=9cmOC = 9 \, \text{cm}.

The accurate solution to the problem is OC=9cm OC = 9 \, \text{cm} .

3

Final Answer

9 cm

Key Points to Remember

Essential concepts to master this topic
  • Property: Triangle areas sharing same base are proportional to their heights
  • Technique: If area ratio is 1:3, then segment ratio AO:OC = 1:3
  • Check: Verify 39=13 \frac{3}{9} = \frac{1}{3} matches the given area ratio ✓

Common Mistakes

Avoid these frequent errors
  • Confusing area ratio with segment ratio
    Don't think if area ratio is 1:3 then OC = 1cm! This ignores that areas are proportional to heights when bases are equal. Always remember: if triangle area ratio is 1:3, then corresponding height ratio is also 1:3, so OC = 3 × 3 = 9cm.

Practice Quiz

Test your knowledge with interactive questions

Indicate the correct answer

The next quadrilateral is:

AAABBBCCCDDD

FAQ

Everything you need to know about this question

Why do triangle areas relate to segments AO and OC?

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In a deltoid, when triangles ABD and BDC share the same base BD, their areas depend only on their heights. Since AO and OC are the perpendicular distances from A and C to line BD, the area ratio equals the height ratio!

How do I set up the proportion correctly?

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Since Area ABDArea BDC=13 \frac{\text{Area ABD}}{\text{Area BDC}} = \frac{1}{3} , we get AOOC=13 \frac{AO}{OC} = \frac{1}{3} . Cross-multiply: 1 × OC = 3 × AO, so OC = 3 × 3 = 9cm.

What makes this shape a deltoid?

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A deltoid is a quadrilateral with two pairs of adjacent sides that are equal. The diagonals intersect at right angles, creating the triangles we're comparing in this problem.

Can I solve this without using ratios?

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Ratios are the most direct method here! You could use coordinate geometry or trigonometry, but the proportional relationship between areas and heights makes ratios much simpler and less error-prone.

What if I got OC = 1cm instead?

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That's a common error! You likely inverted the ratio. Remember: if area ratio is 1:3, the smaller triangle has area 1 and corresponds to the shorter segment AO = 3cm, so OC must be the longer segment.

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