Determine the points of intersection of the function
With the X
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Determine the points of intersection of the function
With the X
To find the points of intersection, follow these steps:
Now, solve the equation:
Step 1: Set , which gives .
Step 2: Set , which gives .
These values are the -coordinates where the function intersects the x-axis. Since the y-coordinates at each of these points is zero, the intersection points are and .
Therefore, the points of intersection are and .
The following function has been graphed below:
\( f(x)=-x^2+5x+6 \)
Calculate points A and B.
The x-axis is where y = 0! To find where the parabola crosses the x-axis, you need to find all x-values that make y equal zero.
You'd need to factor the quadratic first or use other methods like the quadratic formula. Since is already factored, we can use the zero product property directly!
When you have , think: "What number plus 7 equals zero?" The answer is -7, so x = -7. The sign is always opposite to what's in the parentheses.
By definition, any point on the x-axis has a y-coordinate of zero! That's what makes it the x-axis. So intersection points with the x-axis are always in the form (x, 0).
No! A quadratic function can have at most two x-intercepts. It might have exactly two (like this problem), exactly one, or none at all, but never more than two.
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