Finding X-Intercepts of the Quadratic: y = x(x + 5)

Determine the points of intersection of the function

y=x(x+5) y=x(x+5)

With the X

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the intersection points with the X-axis
00:03 At the intersection points with the X-axis, the Y value must = 0
00:12 Substitute Y = 0 and solve for X values
00:16 Find what makes each factor in the product zero
00:20 This is one solution
00:23 This is the second solution
00:28 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Determine the points of intersection of the function

y=x(x+5) y=x(x+5)

With the X

2

Step-by-step solution

To determine the points of intersection with the x-axis for the function y=x(x+5) y = x(x+5) , follow these steps:

  • Step 1: Set the function equal to zero to find the x-intercepts: y=0 y = 0 .
  • Step 2: Solve the equation x(x+5)=0 x(x+5) = 0 .

Considering the product x(x+5)=0 x(x+5) = 0 :

  • If x=0 x = 0 , then one solution is x=0 x = 0 .
  • If x+5=0 x+5 = 0 , then solving for x x gives x=5 x = -5 .

Thus, the two points of intersection with the x-axis are:

(5,0)(-5, 0) and (0,0)(0, 0).

Therefore, the points of intersection of the function y=x(x+5) y = x(x+5) with the x-axis are (5,0)(-5, 0) and (0,0)(0, 0).

3

Final Answer

(5,0),(0,0) (-5,0),(0,0)

Practice Quiz

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The following function has been graphed below:

\( f(x)=-x^2+5x+6 \)

Calculate points A and B.

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