Domain Analysis: Finding Valid Inputs for y=-(x+8/9)²

Quadratic Functions with Domain Restrictions

Find the positive and negative domains of the function below:

y=(x+89)2 y=-\left(x+\frac{8}{9}\right)^2

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+89)2 y=-\left(x+\frac{8}{9}\right)^2

2

Step-by-step solution

To solve the problem, we follow these steps:

  • Step 1: Recognize that the function y=(x+89)2 y = -\left(x + \frac{8}{9}\right)^2 is a quadratic function in vertex form where the leading coefficient a=1 a = -1 .
  • Step 2: Determine the direction of the parabola. Since the coefficient a a is negative, the parabola opens downwards.
  • Step 3: Analyze the function's vertex: The vertex is at x=89 x = -\frac{8}{9} . At this point, y=0 y = 0 , which is the maximum value.
  • Step 4: Consider the behavior of the function on either side of the vertex. Because of the downward opening, y y is negative for all x x except at the vertex itself.
  • Step 5: Conclude the results: The function is negative for all x x , except y=0 y = 0 at x=89 x = -\frac{8}{9} .

Thus, the positive and negative domains are:

x<0:x89 x < 0 : x \ne -\frac{8}{9} (negative domain)

x>0: x > 0 : none (positive domain)

The correct answer choice is:

x<0:x89 x < 0 : x \ne -\frac{8}{9}

x>0: x > 0 : none

3

Final Answer

x<0:x89 x < 0 : x\ne-\frac{8}{9}

x>0: x > 0 : none

Key Points to Remember

Essential concepts to master this topic
  • Vertex Form: Function y=(x+89)2 y = -(x + \frac{8}{9})^2 has vertex at x=89 x = -\frac{8}{9}
  • Direction: Negative coefficient means parabola opens downward, maximum at vertex
  • Check: At vertex x=89 x = -\frac{8}{9} , y=0 y = 0 ; elsewhere y<0 y < 0

Common Mistakes

Avoid these frequent errors
  • Confusing domain with range when finding positive/negative regions
    Don't find where x is positive or negative = wrong focus on input values! The question asks for domains where the function OUTPUT (y-values) is positive or negative. Always analyze where y > 0 and y < 0, not where x > 0 and x < 0.

Practice Quiz

Test your knowledge with interactive questions

The graph of the function below does not intersect the \( x \)-axis.

The parabola's vertex is marked A.

Find all values of \( x \) where
\( f\left(x\right) > 0 \).

AAAX

FAQ

Everything you need to know about this question

What does 'positive and negative domains' actually mean?

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It means finding the x-values where the function output is positive (y > 0) or negative (y < 0). We're looking at the sign of the y-values, not the x-values!

Why is the vertex important for this problem?

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The vertex x=89 x = -\frac{8}{9} is where y = 0 (the maximum). Since the parabola opens downward, this is the only point where y isn't negative. Everywhere else, y < 0.

How do I know the parabola opens downward?

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Look at the coefficient of the squared term! Since we have y=(x+89)2 y = -(x + \frac{8}{9})^2 , the coefficient is -1 (negative), so it opens downward like an upside-down U.

Why is there no positive domain?

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Because this downward-opening parabola has its maximum value of y = 0 at the vertex. Since 0 isn't positive, and all other y-values are negative, there are no x-values that make y positive.

What does the notation 'x ≠ -8/9' mean?

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It means all negative x-values except -8/9. At x = -8/9, y = 0 (not negative). For all other negative x-values, y < 0, so they belong to the negative domain.

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