Domain Analysis: Finding Valid Inputs for y=-(x+8/9)²

Find the positive and negative domains of the function below:

y=(x+89)2 y=-\left(x+\frac{8}{9}\right)^2

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Step-by-step written solution

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1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+89)2 y=-\left(x+\frac{8}{9}\right)^2

2

Step-by-step solution

To solve the problem, we follow these steps:

  • Step 1: Recognize that the function y=(x+89)2 y = -\left(x + \frac{8}{9}\right)^2 is a quadratic function in vertex form where the leading coefficient a=1 a = -1 .
  • Step 2: Determine the direction of the parabola. Since the coefficient a a is negative, the parabola opens downwards.
  • Step 3: Analyze the function's vertex: The vertex is at x=89 x = -\frac{8}{9} . At this point, y=0 y = 0 , which is the maximum value.
  • Step 4: Consider the behavior of the function on either side of the vertex. Because of the downward opening, y y is negative for all x x except at the vertex itself.
  • Step 5: Conclude the results: The function is negative for all x x , except y=0 y = 0 at x=89 x = -\frac{8}{9} .

Thus, the positive and negative domains are:

x<0:x89 x < 0 : x \ne -\frac{8}{9} (negative domain)

x>0: x > 0 : none (positive domain)

The correct answer choice is:

x<0:x89 x < 0 : x \ne -\frac{8}{9}

x>0: x > 0 : none

3

Final Answer

x<0:x89 x < 0 : x\ne-\frac{8}{9}

x>0: x > 0 : none

Practice Quiz

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The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

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