Domain Analysis: Find Valid Inputs for y=-(x+√13)² Function

Find the positive and negative domains of the function below:

y=(x+13)2 y=-\left(x+\sqrt{1}3\right)^2

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Step-by-step written solution

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1

Understand the problem

Find the positive and negative domains of the function below:

y=(x+13)2 y=-\left(x+\sqrt{1}3\right)^2

2

Step-by-step solution

To find the positive and negative domains of the function, let's first analyze the given function y=(x+13)2 y = -\left(x + \sqrt{13}\right)^2 .

  • Step 1: Analyze the function.
    The function is a downward-opening parabola with vertex at (13,0) (-\sqrt{13}, 0) , because the coefficient of the quadratic term is negative.

  • Step 2: Determine the intervals for positive and negative domains.
    A parabola that opens downward from its vertex means the function is negative for all x13 x \neq -\sqrt{13} since there are no values of x that make the function greater than 0 because the vertex is the maximum point.

  • Step 3: Consider the function around the vertex.
    The only point where the function equals zero is at the vertex x=13 x = -\sqrt{13} . Thus, for any other x x , the function is y<0 y < 0 .

Conclusion:
For x<0 x < 0 , the function satisfies the negative characteristic for all domains except x=13 x = -\sqrt{13} where y=0 y = 0 . Thus, the negative domain is x<0:x13 x < 0 : x \neq -\sqrt{13} .

There are no values of x x for which the function becomes positive. Therefore, the positive domain is empty for x>0 x > 0 .

The solution concludes that the positive domain is none, and the negative domain is x<0:x13 x < 0 : x \neq -\sqrt{13} .

3

Final Answer

x<0:x13 x < 0 : x\ne-\sqrt{13}

x>0: x > 0 : none

Practice Quiz

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The graph of the function below intersects the X-axis at points A and B.

The vertex of the parabola is marked at point C.

Find all values of \( x \) where \( f\left(x\right) > 0 \).

AAABBBCCCX

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