Domain Analysis: Find Valid Inputs for y=-(x+√13)² Function

Question

Find the positive and negative domains of the function below:

y=(x+13)2 y=-\left(x+\sqrt{1}3\right)^2

Step-by-Step Solution

To find the positive and negative domains of the function, let's first analyze the given function y=(x+13)2 y = -\left(x + \sqrt{13}\right)^2 .

  • Step 1: Analyze the function.
    The function is a downward-opening parabola with vertex at (13,0) (-\sqrt{13}, 0) , because the coefficient of the quadratic term is negative.

  • Step 2: Determine the intervals for positive and negative domains.
    A parabola that opens downward from its vertex means the function is negative for all x13 x \neq -\sqrt{13} since there are no values of x that make the function greater than 0 because the vertex is the maximum point.

  • Step 3: Consider the function around the vertex.
    The only point where the function equals zero is at the vertex x=13 x = -\sqrt{13} . Thus, for any other x x , the function is y < 0 .

Conclusion:
For x < 0 , the function satisfies the negative characteristic for all domains except x=13 x = -\sqrt{13} where y=0 y = 0 . Thus, the negative domain is x < 0 : x \neq -\sqrt{13} .

There are no values of x x for which the function becomes positive. Therefore, the positive domain is empty for x > 0 .

The solution concludes that the positive domain is none, and the negative domain is x < 0 : x \neq -\sqrt{13} .

Answer

x < 0 : x\ne-\sqrt{13}

x > 0 : none