(a+b)(3+ba)=?
To solve this problem, we'll use the distributive property, which states that for any numbers a, b, and c, a(b+c)=ab+ac.
Let's break it down step by step:
Step 1: Apply the distributive property
We will expand the expression (a+b)(3+ba) by distributing the terms in (a+b) over (3+ba).
Step 2: Expand the expression
(a+b)(3+ba) expands as follows:
- First, distribute a to each term in (3+ba):
- a⋅3=3a
- a⋅ba=ba2
- Next, distribute b to each term in (3+ba):
- b⋅3=3b
- b⋅ba=a (because b cancels with the denominator)
Step 3: Combine and simplify the results
Putting it all together, we have:
3a+ba2+3b+a
Simplify the expression by combining like terms:
- 3a+a=4a
Thus, the simplified result is:
4a+ba2+3b
Therefore, the solution to the problem is 4a+ba2+3b.
4a+ba2+3b