(43+2a)(8a+9ba)−(5+a)(23a+b)=?
To solve this problem, we'll simplify the expression step by step using the distributive law.
Step 1: Apply the distributive property to the first part of the expression: (43+2a)(8a+9ba).
- Distribute 43 to 8a and 9ba: 43×8a=6a and 43×9ba=427ab.
- Distribute 2a to 8a and 9ba: 2a×8a=16a2 and 2a×9ba=18a2b.
The first part expands to: 6a+427ab+16a2+18a2b.
Step 2: Apply the distributive property to the second part of the expression: (5+a)(23a+b).
- Distribute 5 to 23a and b: 5×23a=215a and 5×b=5b.
- Distribute a to 23a and b: a×23a=23a2 and a×b=ab.
The second part expands to: 215a+5b+23a2+ab.
Step 3: Simplify the expression by subtracting the second part from the first:
- Combine like terms: 6a−215a and 427ab−ab.
- Subtract constants and like terms:
- 6a−215a=−23a.
- 427ab−ab=427ab−44ab=423ab.
- (16a2−23a2)+(18a2b−5b).
The full simplified expression is: −23a+423ab+(16a2−23a2)+(18a2b−5b).
Recognize that 16a2−23a2=232a2−23a2=229a2, the final answer is:
The simplified expression is: −23a+543ab+1421a2+(18a2−5)b.
−23a+543ab+1421a2+(18a2−5)b