Calculate the Vertex of y = (x-3)² + 6

To solve the problem of finding the vertex of the parabola $y = (x-3)^2 + 6$, we take the following steps:

Step 1: Identify the form of the given equation.
The equation is given in the vertex form of a quadratic function, which is generally expressed as $y = (x-h)^2 + k$.

Step 2: Recognize the coefficients.
In the given equation $y = (x-3)^2 + 6$, compare it with the standard form $y=(x-h)^2 + k$ to identify $h$ and $k$. Here, $h = 3$ and $k = 6$.

Step 3: Determine the vertex.
The vertex of the parabola, therefore, is directly given by the point $(h, k) = (3, 6)$.

As a conclusion, the vertex of the parabola described by the equation $y = (x-3)^2 + 6$ is located at the point $(3, 6)$.