Find Increasing Intervals for y = 2x² - 4x + 5: Quadratic Function Analysis

Find the intervals where the function is increasing:

y=2x24x+5 y=2x^2-4x+5

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the domains of increase of the function
00:03 We'll use the formula to find the X value at the vertex
00:07 Let's identify the trinomial coefficients
00:11 We'll substitute appropriate values according to the given data, and solve for X
00:20 This is the X value at the vertex point
00:26 The coefficient A is positive, therefore the parabola has a minimum point
00:31 From the graph we can deduce the domains of increase of the function
00:37 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Find the intervals where the function is increasing:

y=2x24x+5 y=2x^2-4x+5

2

Step-by-step solution

To determine where the function y=2x24x+5 y = 2x^2 - 4x + 5 is increasing, we must first find its derivative and analyze its behavior.

Step 1: Find the derivative of y y .
The function given is y=2x24x+5 y = 2x^2 - 4x + 5 . The first derivative, which represents the slope of the tangent at any point x x , is found by differentiating:
y=ddx(2x24x+5)=4x4 y' = \frac{d}{dx}(2x^2 - 4x + 5) = 4x - 4

Step 2: Set the derivative to greater than zero and solve for x x .
We set the inequality to determine where the function is increasing:
4x4>0 4x - 4 > 0

  • Add 4 to both sides to isolate the linear term:
    4x>4 4x > 4
  • Divide both sides by 4 to solve for x x :
    x>1 x > 1

Thus, the function is increasing for all x>1 x > 1 .

Therefore, the correct answer is x>1 x > 1 .

3

Final Answer

x>1 x>1

Practice Quiz

Test your knowledge with interactive questions

Note that the graph of the function shown below does not intersect the x-axis

The parabola's vertex is A

Identify the interval where the function is decreasing:

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