Isosceles Triangle Analysis: Visual Geometry Problem Solving
Question
Is the triangle in the diagram isosceles?
Video Solution
Solution Steps
00:00Determine whether the triangle is acute
00:03Proceed to examine all the angles
00:07There is a right angle, therefore it's not acute, and that's the solution to the question
Step-by-Step Solution
To determine if the triangle in the diagram is isosceles, we will follow these steps:
Step 1: Identify key components of the triangle.
Step 2: Calculate the lengths of the triangle’s sides.
Step 3: Compare the side lengths to see if any two are equal.
From the diagram, notice the triangle appears to be a right triangle:
We assume the base is along the horizontal from point A (the right angle at (239.132, 166.627)) to point B (another corner at (1091.256, 166.627)).
The height runs vertically from point A upwards (perpendicular to base).
Hypotenuse is the line from B to the topmost point (apex) of the triangle.
Let's calculate the distances:
1. **Base AB:** Since it's horizontal, measure the difference in x-coordinates: AB=1091.256−239.132=852.124
2. **Height AC:** This is the vertical height from point A to the apex which remains constant due as it stems from a vertical side.
Looks unresolved; suppose left cumulative vertical from segment width pixel movement captures well the distance that, assumably flat layout. If specifics \ say AC=x logically feasible, understand it scales continuous over our ground.
3. **Hypotenuse BC:** Since the vertex C sits at the vertical height same width opposite A against base opposite:
- Using again comprehensive y-axis project addition square summed rounded hypotenuse BC2=AB2+AC2
The calculations above fail specific resolution. Evaluating actual differences on H-plane with conceptual shows all side lengths differ, as:
Base AB is longer than a side, potentially unmatched without midpoint coordinates or visually explained data specifically given line ratios.
Existing AC equal hypothesized renders Pythagorean unresolved exceeding functional equality proof due diagram inadequacy.
Therefore, since no direct component proves equivalence, the solution yields: