When we have atriangle, we can identify that it is anisosceles if at least one of the following conditions is met:
1) If the triangle has two equal angles - The triangle is isosceles. 2) If in the triangle the height also bisects the angle of the vertex - The triangle is isosceles. 3) If in the triangle the height is also the median - The triangle is isosceles. 4) If in the triangle the median is also the bisector - The triangle is isosceles.
Before we talk about how to identify an isosceles triangle, let's remember that it is a triangle with two sides (or edges) of the same length - This means that the base angles are also equal. Moreover, in an isosceles triangle, the median of the base, the bisector, and the height are the same, that is, they coincide.
Let's see it illustrated
These magnificent properties of the isosceles triangle cannot prove by themselves that it is an isosceles triangle. So, how can we prove that our triangle is isosceles?
If at least one of the following conditions is met: 1) If our triangle has two equal angles - The triangle is isosceles. This derives from the fact that the sides opposite to equal angles are also equal, therefore, if the angles are equal, the sides are too.
2) If in the triangle the altitude also bisects the vertex angle - The triangle is isosceles. 3) If in the triangle the altitude is also the median - The triangle is isosceles. 4) If in the triangle the median is also the angle bisector - The triangle is isosceles. In fact, we can summarize guidelines 2 and 4 and write a single condition: If two of these coincide - the median, the altitude, and the bisector - The triangle is isosceles.
Great, now you know how to identify isosceles triangles easily and quickly.
If you are interested in learning more about other angle topics, you can enter one of the following articles:
Sum of the interior angles of a polygon
Angles in regular hexagons and octagons
Measure of an angle of a regular polygon
Sum of the exterior angles of a polygon
Exterior angle of a triangle
Relationships between angles and sides of the triangle
The relationship between the lengths of the sides of a triangle
In the blog ofTutorelayou will find a variety of articles about mathematics.
Examples and exercises with solutions for identifying an isosceles triangle
examples.example_title
Given an equilateral triangle:
The perimeter of the triangle is 33 cm, what is the value of X?
examples.explanation_title
We know that in an equilateral triangle all sides are equal,
Therefore, if we know that one side is equal to X, all sides are equal to X.
We know that the perimeter of the triangle is 33.
The perimeter of the triangle is equal to the sum of the sides together.
We replace the data:
x+x+x=33
3x=33
We divide the two sections by 3:
33x=333
x=11
examples.solution_title
11
examples.example_title
ABCD is a square with AC as its diagonal.
What kind of triangles are ABC and ACD?
(There may be more than one correct answer!)
examples.explanation_title
Since ABCD is a square, all its angles measure 90 degrees.
Therefore, angles D and B are equal to 90°, that is, they are right angles,
Therefore, the two triangles ABC and ADC are right triangles.
In a square all sides are equal, therefore:
AB=BC=CD=DA
But the diagonal AC is not equal to them.
Therefore, the two previous triangles are isosceles:
AD=DC
AB=BC
examples.solution_title
Right triangles
examples.example_title
ABC is an isosceles triangle.
AD is the height of triangle ABC.
AF = 5
AB = 17 AG = 3
AD = 8
What is the perimeter of the trapezoid EFBC?
examples.explanation_title
To find the perimeter of the trapezoid, all its sides must be added:
We will focus on finding the bases.
To find GF we use the Pythagorean theorem: A2+B2=C2in the triangle AFG
We replace
32+GF2=52
We isolate GF and solve:
9+GF2=25
GF2=25−9=16
GF=4
We perform the same process with the side DB of the triangle ABD:
82+DB2=172
64+DB2=289
DB2=289−64=225
DB=15
We start by finding FB:
FB=AB−AF=17−5=12
Now we reveal EF and CB:
GF=GE=4
DB=DC=15
This is because in an isosceles triangle, the height divides the base into two equal parts so:
EF=GF×2=4×2=8
CB=DB×2=15×2=30
All that's left is to calculate:
30+8+12×2=30+8+24=62
examples.solution_title
62
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