Solve Nested Square Roots: √√16 × √√8 Multiplication Problem

Nested Radicals with Fourth Root Simplification

Complete the following exercise:

168= \sqrt{\sqrt{16}}\cdot\sqrt{\sqrt{8}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 A 'regular' root raised to the second power
00:11 When there is a root of order (C) of root (B)
00:15 The result equals the root of the orders' product
00:22 Apply this formula to our exercise
00:29 When we have a product of 2 numbers (A and B) in a root of order (C)
00:33 The result equals their product (A times B) in a root of order (C)
00:36 Apply this formula to our exercise, and proceed to calculate the product
00:46 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

168= \sqrt{\sqrt{16}}\cdot\sqrt{\sqrt{8}}=

2

Step-by-step solution

To solve the problem 168 \sqrt{\sqrt{16}}\cdot\sqrt{\sqrt{8}} , we will follow these steps:

  • Step 1: Simplify each nested square root expression.
  • Step 2: Multiply the simplified expressions of the roots.

Step 1: Evaluate 16 \sqrt{\sqrt{16}} .
Since 16 can be expressed as 24 2^4 , we have: 16=(161/2)1/2=161/4=(24)1/4=24/4=21=2 \sqrt{\sqrt{16}} = \left(16^{1/2}\right)^{1/2} = 16^{1/4} = \left(2^4\right)^{1/4} = 2^{4/4} = 2^{1} = 2

Evaluate 8 \sqrt{\sqrt{8}} .
Since 8 can be expressed as 23 2^3 , we have: 8=(81/2)1/2=81/4=(23)1/4=23/4 \sqrt{\sqrt{8}} = \left(8^{1/2}\right)^{1/2} = 8^{1/4} = \left(2^3\right)^{1/4} = 2^{3/4}

Step 2: Multiply these simplified expressions together: 223/4=2123/4=21+3/4=27/4 2 \cdot 2^{3/4} = 2^{1} \cdot 2^{3/4} = 2^{1 + 3/4} = 2^{7/4}

Finally, converting back to radical form: 27/4=(27)1/4=274=1284 2^{7/4} = \left(2^7\right)^{1/4} = \sqrt[4]{2^7} = \sqrt[4]{128}

Thus, the solution to the problem is 1284 \sqrt[4]{128} , which corresponds to answer choice 3.

3

Final Answer

1284 \sqrt[4]{128}

Key Points to Remember

Essential concepts to master this topic
  • Rule: Nested square roots combine as exponents: a=a1/4 \sqrt{\sqrt{a}} = a^{1/4}
  • Technique: Express as powers of 2: 168=223/4=27/4 \sqrt{\sqrt{16}} \cdot \sqrt{\sqrt{8}} = 2 \cdot 2^{3/4} = 2^{7/4}
  • Check: Convert back to radical form: 27/4=1284 2^{7/4} = \sqrt[4]{128} since 27=128 2^7 = 128

Common Mistakes

Avoid these frequent errors
  • Multiplying the numbers inside the radicals first
    Don't multiply 16 × 8 = 128 and then work with 128 \sqrt{\sqrt{128}} = wrong approach! This gives 1284 \sqrt[4]{128} by coincidence but uses incorrect logic. Always simplify each nested radical separately first: 16=2 \sqrt{\sqrt{16}} = 2 and 8=23/4 \sqrt{\sqrt{8}} = 2^{3/4} , then multiply.

Practice Quiz

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FAQ

Everything you need to know about this question

What does a nested square root like √√16 actually mean?

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A nested square root means you take the square root twice! First find 16=4 \sqrt{16} = 4 , then find 4=2 \sqrt{4} = 2 . Using exponent rules: 16=161/4 \sqrt{\sqrt{16}} = 16^{1/4} .

Why does √√16 equal 2 but √√8 doesn't equal a whole number?

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Because 16 is a perfect fourth power (24 2^4 ), so 161/4=2 16^{1/4} = 2 . But 8 = 23 2^3 , so 81/4=23/4 8^{1/4} = 2^{3/4} is not a whole number.

How do I know the final answer should be a fourth root?

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When you multiply 2123/4=27/4 2^1 \cdot 2^{3/4} = 2^{7/4} , the denominator 4 in the exponent tells you it's a fourth root: 27/4=274=1284 2^{7/4} = \sqrt[4]{2^7} = \sqrt[4]{128} .

Can I use a calculator to check this?

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Yes! Calculate 16×8 \sqrt{\sqrt{16}} \times \sqrt{\sqrt{8}} and 1284 \sqrt[4]{128} separately. Both should give approximately 3.364.

What's the difference between √128 and ∜128?

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12811.3 \sqrt{128} \approx 11.3 (square root), while 12843.36 \sqrt[4]{128} \approx 3.36 (fourth root). The fourth root is much smaller because you're asking "what number to the 4th power equals 128?"

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