Multiply and Simplify: (⁵√√3) × (⁵√√3) Radical Expression

Radical Multiplication with Nested Roots

Complete the following exercise:

3535= \sqrt[5]{\sqrt{3}}\cdot\sqrt[5]{\sqrt{3}}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 A 'regular' root raised to the second power
00:13 When there is a root of order (C) of root (B)
00:18 The result equals the root of the orders' product
00:21 Apply this formula to our exercise
00:33 When we have a product of 2 numbers (A and B) in a root of order (C)
00:36 The result equals their product (A times B) in a root of order (C)
00:39 Apply this formula to our exercise
00:46 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

3535= \sqrt[5]{\sqrt{3}}\cdot\sqrt[5]{\sqrt{3}}=

2

Step-by-step solution

To solve the problem 3535=\sqrt[5]{\sqrt{3}} \cdot \sqrt[5]{\sqrt{3}} = , we follow these steps:

Step 1: Express each root using exponents.
35\sqrt[5]{\sqrt{3}} can be rewritten as (31/2)1/5(3^{1/2})^{1/5}, which simplifies to 31/103^{1/10} using the law (am)n=amn(a^m)^n = a^{m \cdot n}.

Step 2: Multiply the expressions.
We have (31/10)(31/10)(3^{1/10}) \cdot (3^{1/10}). According to the laws of exponents, aman=am+na^m \cdot a^n = a^{m+n}. Thus, the expression becomes 31/10+1/10=32/10=31/53^{1/10 + 1/10} = 3^{2/10} = 3^{1/5}.

Step 3: Convert back to a root, if necessary.
The expression 31/53^{1/5} corresponds to 35\sqrt[5]{3}.

Therefore, the expression 3535\sqrt[5]{\sqrt{3}} \cdot \sqrt[5]{\sqrt{3}} simplifies to 31/53^{1/5}, which is equivalent to 95\sqrt[5]{9}.

To match with the given choices, observe that 31/53^{1/5} can also be expressed as 910\sqrt[10]{9} because 31/5=(32)1/103^{1/5} = (3^2)^{1/10}, which equals to 910\sqrt[10]{9}.

The correct answer is choice 4, 910\sqrt[10]{9}.

3

Final Answer

910 \sqrt[10]{9}

Key Points to Remember

Essential concepts to master this topic
  • Exponent Rule: Convert nested radicals using (am)n=amn (a^m)^n = a^{mn}
  • Technique: 35=31/10 \sqrt[5]{\sqrt{3}} = 3^{1/10} , then multiply: 31/1031/10=32/10 3^{1/10} \cdot 3^{1/10} = 3^{2/10}
  • Check: Verify 31/5=(32)1/10=910 3^{1/5} = (3^2)^{1/10} = \sqrt[10]{9} matches answer choices ✓

Common Mistakes

Avoid these frequent errors
  • Directly multiplying the inner radicands
    Don't multiply √3 × √3 = 3 inside the fifth root = ⁵√3! This ignores the nested structure completely. The outer root affects how inner expressions combine. Always convert to exponential form first: ⁵√√3 = 3^(1/10), then apply multiplication rules.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt{\frac{2}{4}}= \)

FAQ

Everything you need to know about this question

Why can't I just multiply the √3 parts together first?

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Because the fifth roots are applied to each √3 separately! You must follow the order of operations: work from inside out, converting each nested radical to exponential form before multiplying.

How do I convert nested radicals to exponents?

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Work step by step: 35=31/25=(31/2)1/5=31/10 \sqrt[5]{\sqrt{3}} = \sqrt[5]{3^{1/2}} = (3^{1/2})^{1/5} = 3^{1/10} . The key is using (a^m)^n = a^(mn).

Why is the answer ¹⁰√9 and not ⁵√3?

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When you multiply 31/10×31/10=32/10=31/5 3^{1/10} \times 3^{1/10} = 3^{2/10} = 3^{1/5} , this equals 35 \sqrt[5]{3} . But 3¹/⁵ also equals (3²)¹/¹⁰ = √¹⁰9, which matches the given choices!

Can I use the property ⁿ√a × ⁿ√b = ⁿ√(ab)?

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Yes! Since both terms have the same index (5), you can write: 35×35=3×35=35 \sqrt[5]{\sqrt{3}} \times \sqrt[5]{\sqrt{3}} = \sqrt[5]{\sqrt{3} \times \sqrt{3}} = \sqrt[5]{3} .

How do I know which form of the answer to choose?

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Always check which forms are available in the answer choices! 31/5 3^{1/5} can be written as 35 \sqrt[5]{3} or 910 \sqrt[10]{9} - pick the one that matches the options.

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