Rectangle Diagonal Problem: Calculate Triangle Area with BO = 8.5 and AD = 8

Rectangle Diagonal Theorem with Pythagorean Application

Below is the rectangle ABCD.

O is the intersection point of the diagonals of the rectangle.

AD = 8

BO = 8.5

Calculate the area of the triangle ABD.

AAABBBCCCDDDOOO8.58

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1

Understand the problem

Below is the rectangle ABCD.

O is the intersection point of the diagonals of the rectangle.

AD = 8

BO = 8.5

Calculate the area of the triangle ABD.

AAABBBCCCDDDOOO8.58

2

Step-by-step solution

According to the given information, we can claim that:

BD=2BO=8.5×2=17 BD=2BO=8.5\times2=17

Now let's look at triangle ABD to calculate side AB

AB2+AD2=BD2 AB^2+AD^2=BD^2

Let's input the known data:

AB2+82=172 AB^2+8^2=17^2

AB2=28964=225 AB^2=289-64=225

We'll take the square root

AB=15 AB=15

Now let's calculate the area of triangle ABD:

15×82=1202=60 \frac{15\times8}{2}=\frac{120}{2}=60

3

Final Answer

60

Key Points to Remember

Essential concepts to master this topic
  • Diagonal Property: In a rectangle, diagonals bisect each other equally
  • Technique: Use BD=2×BO=2×8.5=17 BD = 2 \times BO = 2 \times 8.5 = 17
  • Check: Verify with Pythagorean: 152+82=225+64=289=172 15^2 + 8^2 = 225 + 64 = 289 = 17^2

Common Mistakes

Avoid these frequent errors
  • Confusing BO with the full diagonal BD
    Don't use BO = 8.5 as the full diagonal length = area of 30! The intersection point O divides each diagonal in half, so BO is only half of diagonal BD. Always remember BD = 2 × BO to get the complete diagonal length.

Practice Quiz

Test your knowledge with interactive questions

The points A and O are shown in the figure below.

Is it possible to draw a rectangle so that the side AO is its diagonal?

AAAOOO

FAQ

Everything you need to know about this question

Why is BD equal to 2 times BO?

+

In any rectangle, the diagonals bisect each other at point O. This means O is exactly halfway along each diagonal, so BO = half of BD. Therefore, the full diagonal BD = 2 × BO.

How do I know triangle ABD is a right triangle?

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Triangle ABD has a right angle at A because ABCD is a rectangle. All corners of a rectangle are 90°, making ABD a right triangle with the diagonal BD as its hypotenuse.

Can I use the diagonal formula instead of Pythagorean theorem?

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Yes! For a rectangle with sides a and b, diagonal = a2+b2 \sqrt{a^2 + b^2} . Since BD = 17 and AD = 8, you get: 17=AB2+82 17 = \sqrt{AB^2 + 8^2} , leading to the same answer AB = 15.

Why do I calculate the area using AD and AB instead of the diagonal?

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Triangle area formula needs the base and height, which must be perpendicular. In right triangle ABD, sides AD and AB are perpendicular, so Area = 12×AD×AB \frac{1}{2} \times AD \times AB .

What if I calculated AB incorrectly?

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Always verify using the Pythagorean theorem! If AB = 15, then 152+82=225+64=289 15^2 + 8^2 = 225 + 64 = 289 , and 289=17 \sqrt{289} = 17 ✓. This confirms your AB value is correct.

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