Simplify the Exponential Product: 3^x ⋅ 2^x ⋅ 3^(2x)

3x2x32x= 3^x\cdot2^x\cdot3^{2x}=

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1

Understand the problem

3x2x32x= 3^x\cdot2^x\cdot3^{2x}=

2

Step-by-step solution

In this case we have 2 different bases, so we will add what can be added, that is, the exponents of 3 3

3x2x32x=2x33x 3^x\cdot2^x\cdot3^{2x}=2^x\cdot3^{3x}

3

Final Answer

33x2x 3^{3x}\cdot2^x

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\( 112^0=\text{?} \)

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