Simplify E⁶·F⁻⁴·E⁰·F⁷·E: Multiple Exponent Operations

Grouping makes it much easier to apply the power rule correctly! When you see $E^6 \cdot F^{-4} \cdot E^0 \cdot F^7 \cdot E$, rearrange to $E^6 \cdot E^0 \cdot E \cdot F^{-4} \cdot F^7$ so you can work with each variable separately.

$E^0 = 1$ for any non-zero base! However, when multiplying terms, you still add the exponent 0 to your sum. So $E^6 \cdot E^0 = E^{6+0} = E^6$.

Remember that $E = E^1$! Any variable without a visible exponent has an implied exponent of 1. So when adding exponents: 6 + 0 + 1 = 7.

Absolutely! Negative exponents follow the same addition rule. For the F terms: $F^{-4} \cdot F^7 = F^{-4+7} = F^3$. Just add the exponents normally.

Work with one variable at a time! First handle all E terms, then all F terms. Write them as separate factors: $E^7 \cdot F^3$ is your final answer.

Count the original terms: you should have 3 E-terms and 2 F-terms. Your final answer should reflect this by having both E and F with positive exponents. $E^7 \cdot F^3$ makes sense! ✓