Examples with solutions for Multiplication of Powers: Variables in the exponent of the power

Exercise #1

Reduce the following equation:

10a+b×10a+1×10b+1= 10^{a+b}\times10^{a+1}\times10^{b+1}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the exponents in the given expression.
  • Step 2: Use the property of exponents for multiplication by like bases.
  • Step 3: Add the exponents together and simplify.

Now, let's work through each step:

Step 1: The original expression is 10a+b×10a+1×10b+1 10^{a+b} \times 10^{a+1} \times 10^{b+1} .

Step 2: Since the base (10) is the same for all terms, we add the exponents:

(a+b)+(a+1)+(b+1) (a+b) + (a+1) + (b+1)

Step 3: Simplifying further:

a+b+a+1+b+1=2a+2b+2 a + b + a + 1 + b + 1 = 2a + 2b + 2

Thus, the expression simplifies to:

102a+2b+2 10^{2a + 2b + 2}

Therefore, the solution to the problem is 102b+2a+2 10^{2b+2a+2} .

Answer

102b+2a+2 10^{2b+2a+2}

Exercise #2

Reduce the following equation:

2a×22= 2^a\times2^2=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the common base
  • Step 2: Apply the property of exponents
  • Step 3: Simplify the expression

Now, let's work through each step:

Step 1: The problem gives us the expression 2a×22 2^a \times 2^2 . Here, the common base is 2.
Step 2: We'll apply the property of exponents, which states that for the same base, you add the exponents: bm×bn=bm+n b^m \times b^n = b^{m+n} . In this case, it will be 2a+2 2^{a+2} .
Step 3: Rewriting the expression using this rule, we get: 2a×22=2a+2 2^a \times 2^2 = 2^{a+2} .

Therefore, the solution to the problem is 2a+2 2^{a+2} .

Answer

2a+2 2^{a+2}

Exercise #3

34×3x= 3^4\times3^x=

Video Solution

Step-by-Step Solution

To solve this problem, we'll apply the exponent rule for multiplying powers with the same base.

  • Step 1: Identify the base. The base for both terms is 3.
  • Step 2: Apply the multiplication of powers rule. According to the rule, when multiplying powers with the same base, we add their exponents: 34×3x=34+x 3^4 \times 3^x = 3^{4+x} .
  • Step 3: Write down the simplified form of the expression. The simplified expression of 34×3x 3^4 \times 3^x is: 34+x 3^{4+x}

Therefore, the solution to the expression 34×3x 3^4 \times 3^x simplifies to 34+x 3^{4+x} .

Hence, the correct choice is 34+x 3^{4+x} , matching answer choice 1.

Answer

34+x 3^{4+x}

Exercise #4

Reduce the following equation:

4x×42×4a= 4^x\times4^2\times4^a=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Confirm the given expression is 4x×42×4a 4^x \times 4^2 \times 4^a .
  • Step 2: Apply the exponent rule for multiplication of powers: if bm×bn=bm+n b^m \times b^n = b^{m+n} , use this with base 4.
  • Step 3: Add the exponents of each term.

Let's work through these steps:

Step 1: The expression we have is 4x×42×4a 4^x \times 4^2 \times 4^a .

Step 2: Since all parts of the product have the same base 4 4 , we can use the rule for multiplying powers: 4x×42×4a=4x+2+a 4^x \times 4^2 \times 4^a = 4^{x+2+a} .

Step 3: The simplified expression is obtained by adding the exponents: x+2+a x + 2 + a .

Therefore, the expression 4x×42×4a 4^x \times 4^2 \times 4^a simplifies to 4x+2+a 4^{x+2+a} .

Answer

4x+2+a 4^{x+2+a}

Exercise #5

4x×4x= 4^x\times4^x=

Video Solution

Step-by-Step Solution

To solve this problem, we will follow these steps:

  • Step 1: Identify the given expression and the operation.

  • Step 2: Apply the rule for multiplying powers with the same base.

  • Step 3: Simplify the expression to reach the final answer.

Let's proceed with the solution:
Step 1: We are given the expression 4x×4x4^x \times 4^x. Both terms have the same base of 4 and an exponent of xx.

Step 2: According to the exponent multiplication rule, am×an=am+na^m \times a^n = a^{m+n}. Here, since both bases are 4, we can simplify using this rule.

Step 3: We add the exponents, giving us:

4x×4x=4x+x=42x 4^x \times 4^x = 4^{x+x} = 4^{2x}

Therefore, the correct solution to the problem is 4x+x 4^{x+x} .

Answer

4x+x 4^{x+x}

Exercise #6

Reduce the following equation:

52x×5x= 5^{2x}\times5^x=

Video Solution

Step-by-Step Solution

To reduce the expression 52x×5x 5^{2x} \times 5^x , we will use the exponent multiplication rule:

When multiplying powers with the same base, add the exponents:
Thus, 52x×5x=52x+x 5^{2x} \times 5^x = 5^{2x + x} .

Hence, the correct choice is: 52x+x 5^{2x + x} .

Answer

52x+x 5^{2x+x}

Exercise #7

52×5a×53= 5^2\times5^a\times5^3=

Video Solution

Step-by-Step Solution

To solve the expression 52×5a×535^2 \times 5^a \times 5^3, we will make use of the exponent rule for multiplication, which states that if you multiply powers with the same base, you add the exponents:

am×an=am+n a^m \times a^n = a^{m+n}

Let's apply this rule step by step:

  • Step 1: Identify the base of the power terms. In this problem, the base is 55.
  • Step 2: Write down all the exponents. The exponents we have are 22, aa, and 33.
  • Step 3: Add the exponents together:
    2+a+32 + a + 3.
  • Step 4: Simplify the sum: 2+a+3=5+a2 + a + 3 = 5 + a.
  • Step 5: Express the final result as a single power:
    The expression can be rewritten using the exponent rule as 55+a5^{5+a}.

Thus, the final simplified expression is 55+a 5^{5+a} .

Answer

55+a 5^{5+a}

Exercise #8

3x2x32x= 3^x\cdot2^x\cdot3^{2x}=

Video Solution

Step-by-Step Solution

In this case we have 2 different bases, so we will add what can be added, that is, the exponents of 3 3

3x2x32x=2x33x 3^x\cdot2^x\cdot3^{2x}=2^x\cdot3^{3x}

Answer

33x2x 3^{3x}\cdot2^x

Exercise #9

7x+1×7x= 7^{x+1}\times7^x=

Video Solution

Step-by-Step Solution

To solve the problem 7x+1×7x7^{x+1}\times7^x, follow these steps:

Step 1: Use the rule for multiplying powers with the same base:

aman=am+na^m \cdot a^n = a^{m+n}

Here, the base aa is 77, and the exponents are x+1x+1 and xx.

Step 2: Add the exponents:

The expression becomes 7(x+1)+x7^{(x+1) + x}.

Step 3: Simplify the exponents:

(x+1)+x=2x+1(x+1) + x = 2x + 1

Step 4: Write the final expression:

The simplified expression is 72x+17^{2x+1}.

Therefore, our solution matches choice 3.

The solution to the problem is 72x+1 7^{2x+1} .

Answer

72x+1 7^{2x+1}

Exercise #10

Reduce the following equation:

8a×82×8x= 8^a\times8^2\times8^x=

Video Solution

Step-by-Step Solution

To solve this problem, we'll use the property of exponents for multiplying powers with the same base:

  • Step 1: Identify that all terms have the same base, which is 88. The equation is given as 8a×82×8x8^a \times 8^2 \times 8^x.

  • Step 2: Apply the multiplication property of exponents: bm×bn=bm+nb^m \times b^n = b^{m+n}.

  • Step 3: Add the exponents: (a)+(2)+(x)(a) + (2) + (x) to get the new exponent for the single base.

By applying these steps, we obtain:

8a+2+x8^{a+2+x}

This result matches choice 1, confirming that this is the correct simplified expression.

Answer

8a+2+x 8^{a+2+x}

Exercise #11

22x+12523x= 2^{2x+1}\cdot2^5\cdot2^{3x}=

Video Solution

Step-by-Step Solution

We'll use the law of exponents for multiplying terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n}
Note that this law applies to any number of terms being multiplied, not just two terms. For example, when multiplying three terms with the same base, we get:

amanak=am+nak=am+n+k a^m\cdot a^n\cdot a^k=a^{m+n}\cdot a^k=a^{m+n+k}
When we used the above law of exponents twice, we can also perform the same calculation for four terms in multiplication and so on...

Let's return to the problem:

Notice that all terms in the multiplication have the same base, so we'll use the above law:

22x+12523x=22x+1+5+3x=25x+6 2^{2x+1}\cdot2^5\cdot2^{3x}=2^{2x+1+5+3x}=2^{5x+6}

Therefore, the correct answer is a.

Answer

25x+6 2^{5x+6}

Exercise #12

Expand the following equation:

22a+a= 2^{2a+a}=

Video Solution

Step-by-Step Solution

To solve the problem, we can follow these steps:

  • Step 1: Recognize that the given expression is 22a+a 2^{2a+a} .
  • Step 2: Use the Power of a Power Rule for exponents, which allows us to write am+n=am×an a^{m+n} = a^m \times a^n .
  • Step 3: Rewrite the expression as follows:

Given: 22a+a 2^{2a+a}

Step 4: Simplify the exponent by splitting it:

Since the expression in the exponent is 2a+a 2a+a , we can write:

22a+a=22a×2a 2^{2a+a} = 2^{2a} \times 2^a

Thus, applying the properties of exponents correctly leads us to the expanded form.

Therefore, the expanded equation is 22a×2a 2^{2a} \times 2^a .

Answer

22a×2a 2^{2a}\times2^a

Exercise #13

Expand the following equation:

32a+x+a= 3^{2a+x+a}=

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Analyze the given expression's exponent.
  • Step 2: Apply the exponent addition rule to expand the expression.
  • Step 3: Identify the correct choice from a set of given options.

Now, let's work through each step:
Step 1: The expression given is 32a+x+a 3^{2a + x + a} . Here the exponent is 2a+x+a 2a + x + a .
Step 2: We apply the rule bm+n=bm×bn b^{m+n} = b^m \times b^n by rewriting the exponent sum as individual terms: (2a) (2a) , x x , and a a .
Thus, we can rewrite the expression using the property of exponents: 32a+x+a=32a×3x×3a 3^{2a + x + a} = 3^{2a} \times 3^x \times 3^a .
Step 3: Upon expanding, the solution corresponds to option :

32a×3x×3a 3^{2a}\times3^x\times3^a

.

Therefore, the expanded expression is 32a×3x×3a 3^{2a}\times3^x\times3^a .

Answer

32a×3x×3a 3^{2a}\times3^x\times3^a

Exercise #14

42y454y46= 4^{2y}\cdot4^{-5}\cdot4^{-y}\cdot4^6=

Video Solution

Step-by-Step Solution

We use the power property to multiply terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n}
We apply the property for this problem:

42y454y46=42y+(5)+(y)+6=42y5y+6 4^{2y}\cdot4^{-5}\cdot4^{-y}\cdot4^6= 4^{2y+(-5)+(-y)+6}=4^{2y-5-y+6}
We simplify the expression we got in the last step:

42y5y+6=4y+1 4^{2y-5-y+6} =4^{y+1}
When we add similar terms in the exponent.

Therefore, the correct answer is option c.

Answer

4y+1 4^{y+1}

Exercise #15

Expand the following equation:

4a+b+c= 4^{a+b+c}=

Video Solution

Step-by-Step Solution

To solve this problem, we will use the rule of exponents that allows us to expand the sum a+b+c a + b + c in the exponent:

  • Given: 4a+b+c 4^{a+b+c}
  • According to the exponent rule xm+n+p=xm×xn×xp x^{m+n+p} = x^m \times x^n \times x^p , we can express:
  • Step: Break down 4a+b+c 4^{a+b+c} to:
  • 4a×4b×4c 4^a \times 4^b \times 4^c

Therefore, the expanded form of the equation is 4a×4b×4c 4^a \times 4^b \times 4^c .

Answer

4a×4b×4c 4^a\times4^b\times4^c

Exercise #16

Expand the following equation:

72x+7= 7^{2x+7}=

Video Solution

Step-by-Step Solution

To tackle this problem, we need to expand the expression 72x+7 7^{2x+7} using the properties of exponents:

  • Step 1: Identify the structure of the exponent in the form 2x+7 2x + 7 .
  • Step 2: Recognize this as a sum of two components: 2x 2x and 7 7 .
  • Step 3: Apply the exponent rule am+n=am×an a^{m+n} = a^m \times a^n to separate the expression into two distinct exponent terms.

Now, let's proceed with the solution:

Step 1: Given the exponent is 2x+7 2x + 7 , break it down into individual components:
2x+7=x+x+7 2x + 7 = x + x + 7 .

Step 2: Applying the rule am+n=am×an a^{m+n} = a^m \times a^n :
72x+7=7x+x+7=7x×7x+7 7^{2x+7} = 7^{x+x+7} = 7^x \times 7^{x+7} .

Therefore, the expanded form of the expression is 7x×7x+7 7^x \times 7^{x+7} .

Answer

7x×7x+7 7^x\times7^{x+7}

Exercise #17

72x+1717x= 7^{2x+1}\cdot7^{-1}\cdot7^x=

Video Solution

Step-by-Step Solution

We use the power property to multiply terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n} We apply the property to our expression:

72x+1717x=72x+1+(1)+x=72x+11+x 7^{2x+1}\cdot7^{-1}\cdot7^x=7^{2x+1+(-1)+x}=7^{2x+1-1+x} We simplify the expression we got in the last step:

72x+11+x=73x 7^{2x+1-1+x}=7^{3x} When we add similar terms in the exponent.

Therefore, the correct answer is option d.

Answer

73x 7^{3x}

Exercise #18

Expand the following equation:

g10a+5x= g^{10a+5x}=

Video Solution

Step-by-Step Solution

To solve this problem, we will use the properties of exponents:

  • Step 1: Recognize that the exponent 10a+5x 10a + 5x can be expressed as the sum of two terms, namely (5a+5x)+5a (5a + 5x) + 5a .
  • Step 2: Apply the property gm+n=gm×gn g^{m+n} = g^{m} \times g^{n} to the expression g10a+5x g^{10a + 5x} .
  • Step 3: Expand the expression using the identified split:
    Since 10a+5x=(5a+5x)+5a 10a + 5x = (5a + 5x) + 5a , we have:
    g10a+5x=g(5a+5x)+5a=g5a+5x×g5a g^{10a + 5x} = g^{(5a + 5x) + 5a} = g^{5a + 5x} \times g^{5a} .

Thus, the expanded form of the expression is given by g5a+5x×g5a g^{5a+5x} \times g^{5a} .

Answer

g5a+5x×g5a g^{5a+5x}\times g^{5a}

Exercise #19

Solve the following problem:

x3y4x4z6x3+y= x^3\cdot y^4\cdot x^4\cdot z^6\cdot x^{3+y}=

Video Solution

Step-by-Step Solution

Begin by applying the distributive property of multiplication in order to arrange the algebraic expression according to like terms:

x3x4x3+yy4z6 x^3x^4x^{3+y}y^4z^6

Next, we'll use the law of exponents to multiply terms with the same base:

aman=am+n a^m\cdot a^n=a^{m+n}

Note that this law applies to any number of terms being multiplied, not just two. For example, when multiplying three terms with the same base, we obtain the following:

amanak=am+nak=am+n+k a^m\cdot a^n\cdot a^k=a^{m+n}\cdot a^k=a^{m+n+k}

Therefore, we can combine all terms with the same base under one base:

x3+4+3+yy4z6=x10+yy4z6 x^{3+4+3+y}y^4z^6=x^{10+y}y^4z^6

In the second step we simply added the exponents together.

Note that we could only combine terms with the same base using this law,

From here we can see that the expression cannot be simplified further, and therefore this is the correct and final answer which is answer D.

Answer

x10+yy4z6 x^{10+y}\cdot y^4\cdot z^6

Exercise #20

173173x1717x=? \frac{17^{-3}\cdot17^{3x}}{17}-17x=\text{?}

Video Solution

Step-by-Step Solution

Let's deal with the first term in the problem, which is the fraction,

For this, we'll recall two laws of exponents:

a. The law of exponents for multiplication between terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n} b. The law of exponents for division between terms with identical bases:

aman=amn \frac{a^m}{a^n}=a^{m-n} Let's apply these laws of exponents to the problem:

173173x1717x=173+3x1717x=173+3x117x=173x417x \frac{17^{-3}\cdot17^{3x}}{17}-17x=\frac{17^{-3+3x}}{17}-17x=17^{-3+3x-1}-17x=17^{3x-4}-17x where in the first stage we'll apply the law of exponents mentioned in 'a' above to the fraction's numerator, and in the next stage we'll apply the law of exponents mentioned in 'b' to the resulting expression, then we'll simplify the expression.

Therefore, the correct answer is answer a.

Answer

173x417x 17^{3x-4}-17x