Simplify the Expression: 5x²/(3y·20x) Step-by-Step Solution

5x2/(3y20x)=? 5x^2/(3y\cdot20x)=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Let's write division as a fraction
00:12 Let's break X squared into its multiplication with itself
00:20 Let's factorize 20 into factors 5 and 4
00:30 Let's reduce what we can
00:42 Let's calculate 3 times 4
00:48 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

5x2/(3y20x)=? 5x^2/(3y\cdot20x)=\text{?}

2

Step-by-step solution

Let's write the exercise as a fraction:

5x23y×20x= \frac{5x^2}{3y\times20x}=

We'll factor the numerator of the fraction into a multiplication exercise:

5x×x3y×20x= \frac{5x\times x}{3y\times20x}=

Let's write the 20 in the denominator of the fraction as a smaller multiplication exercise:

5x×x3y×4×5x= \frac{5x\times x}{3y\times4\times5x}=

We'll cancel out the 5x in both the numerator and denominator of the fraction:

x3y×4= \frac{x}{3y\times4}=

Let's multiply the denominator of the fraction:

x12y \frac{x}{12y}

3

Final Answer

x12y \frac{x}{12y}

Practice Quiz

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\( 100-(5+55)= \)

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